Answer:
The equation for the amount of dollars pledged in total is f(M) = 2.00M + 7.25, and the amount for just Kiara is f(M) = 0.25M + 5.25
Step-by-step explanation:
The amount they pledge up front is a constant and therefore need to be added to the end of the equation. The amount per mile should be a variable amount. This gets multiplied by the M variable. So we start with the Kiara amount.
0.25 per mile = 0.25M
5.25 pledged = 5.25
Now put them together to get f(M) = 0.25M + 5.25
Do the same with Mark.
1.75 per mile = 1.75M
2.00 pledged = 2.00
Now put them together to get f(M) = 1.75M + 2.00
To get the final total, we add both equations together.
f(M) = 0.25M + 5.25 + 1.75M + 2.00
f(M) = 2.00M + 7.25
320 portions of waffles can be made with one container.
Step-by-step explanation:
Given,
Milk is bought in 1 gallon container.
One portion of waffles require = 0.4 ounces of milk
We know that;
1 gallon = 128 ounces
Now;
No. of portions of waffles = 
No. of portions of waffles = 
No. of portions of waffles = 320
320 portions of waffles can be made with one container.
2x+4y=8
-2x -2x
4y=-2x+8
/4 /4 /4
y=-1/2x+2
Answer:
1. Objective function is a maximum at (16,0), Z = 4x+4y = 4(16) + 4(0) = 64
2. Objective function is at a maximum at (5,3), Z=3x+2y=3(5)+2(3)=21
Step-by-step explanation:
1. Maximize: P = 4x +4y
Subject to: 2x + y ≤ 20
x + 2y ≤ 16
x, y ≥ 0
Plot the constraints and the objective function Z, or P=4x+4y)
Push the objective function to the limit permitted by the feasible region to find the maximum.
Answer: Objective function is a maximum at (16,0),
Z = 4x+4y = 4(16) + 4(0) = 64
2. Maximize P = 3x + 2y
Subject to x + y ≤ 8
2x + y ≤ 13
x ≥ 0, y ≥ 0
Plot the constraints and the objective function Z, or P=3x+2y.
Push the objective function to the limit in the increase + direction permitted by the feasible region to find the maximum intersection.
Answer: Objective function is at a maximum at (5,3),
Z = 3x+2y = 3(5)+2(3) = 21