A right square pyramid is show below

A tin has asquare base whose sides measures 32 cm .the vertical sides are 50cm high.cake mixture is poured into the tin and leve

zepelin [54]

Answer:

(a) V = 51200 cubic cm

(b) V' = 38912 cubic cm

(c) V'' = V - V' = 12288 cubic cm

Step-by-step explanation:

side of the square base, s = 32 cm

height, h = 50 cm

height of cake mixture, h' = 38 cm

(a) The capacity of the tin is the volume.

Capacity of tin, V = s x s x h = 32 x 32 x 50 = 51200 cubic cm

(b) The volume of the cake mixture is

V' = s x s x h'

V' = 32 x 32 x 38 = 38912 cubic cm

(c) Volume of unoccupied space is

V'' = V - V' = 51200 - 38912 = 12288 cubic cm

6 0

3 years ago

80% of what how many games is 32 games?

Talja [164]

40 games would be 100% if 32 games is 80%

6 0

3 years ago

the probability tree diagram shows the probabilities that a football team will win their first two games find the probability of

nevsk [136]

Answer:1/2

Step-by-step explanation:

7 0

2 years ago

Solve the following initial-value problem, showing all work, including a clear general solution as well as the particular soluti

Vikki [24]

Answer:

General Solution is $y=x^{3}+cx^{2}$ and the particular solution is $y=x^{3}-\frac{1}{2}x^{2}$

Step-by-step explanation:

$x\frac{\mathrm{dy} }{\mathrm{d} x}=x^{3}+3y\\\\Rearranging \\\\x\frac{\mathrm{dy} }{\mathrm{d} x}-3y=x^{3}\\\\\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{3y}{x}=x^{2}$

This is a linear diffrential equation of type

$\frac{\mathrm{d} y}{\mathrm{d} x}+p(x)y=q(x)$ ..................(i)

here $p(x)=\frac{-2}{x}$

$q(x)=x^{2}$

The solution of equation i is given by

$y\times e^{\int p(x)dx}=\int e^{\int p(x)dx}\times q(x)dx$

we have $e^{\int p(x)dx}=e^{\int \frac{-2}{x}dx}\\\\e^{\int \frac{-2}{x}dx}=e^{-2ln(x)}\\\\=e^{ln(x^{-2})}\\\\=\frac{1}{x^{2} } \\\\\because e^{ln(f(x))}=f(x)]\\\\Thus\\\\e^{\int p(x)dx}=\frac{1}{x^{2}}$