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kiruha [24]
3 years ago
5

A right square pyramid is show below

Mathematics
1 answer:
anyanavicka [17]3 years ago
3 0
Hi i think you forgot to attach the picture
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PLEASE IM BEGGING ILL CROWN IF I CAN PLEASE HELP
kirill115 [55]

Answer:

$450

Step-by-step explanation:

3 0
3 years ago
Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
3 years ago
I need math help please.
meriva

Answer:

B

Step-by-step explanation:

this is because 8*10= 80 and 80*6=480 so your <u><em>answer is 480</em></u>

8 0
3 years ago
A survey of 80 students found that 24 students both play in the band and play a sport. But 22 students are not in band and do no
Serga [27]

Answer:

yes

Step-by-step explanation:

mark me brainlist please

6 0
3 years ago
Read 2 more answers
PLZ HELP ASAP CIRCLES PART 2
Sveta_85 [38]
For this case we have the following angle:
 theta = (9/5) pi
 Having the conversion we have:
 theta = ((9/5) pi) * (180 / pi)
 Rewriting we have:
 theta = (9/5) * (180)
 theta = (9/5) * (180)
 theta = 324 degrees
 Answer:
 
The angle is equivalent to:
 
theta = 324 degrees
5 0
3 years ago
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