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pantera1 [17]
3 years ago
9

1-A rock that contains evidence of past animal or plant life is called a

Biology
1 answer:
andrezito [222]3 years ago
4 0

Answer:

1. A rock that contains evidence of past animal or plant life is called a <u>fossil</u>.

2. Prehistoric  <u>Woolly Mammoth</u> have been discovered in permafrost in Alaska and Siberia.

3. Hardened tree sap can preserve animals in a substance called <u>amber</u>.

4. Fossils can be created by replacement using minerals such as <u>silica</u>, <u>calcite</u>, <u>pyrite</u>.

5. A  <u>mold</u> shows the original shape of the plant or animal.

6. A cast represents a  <u>solid</u> version of the original plant or animal.

7. Trails, tracks and burrows are examples of  <u>trace</u> fossils.

8. Some of the oldest fossils on earth are from ancient  <u>worms</u> crawling on the seafloor.

Explanation:

Fossils are known to be the remains of plants and animals which have been preserved and kept in rock. They are usually a shell, skeleton or plant fiber that has been buried.  Over time, they turned into rock.

Fossil amber are known to be fossil insects that are preserved in hardened tree sap. These insects and some small animal or plant that are found in these hardened tree sap were trapped in the tree.

Woolly Mammoth is known to be a closest extant relative to the Asian elephant. The appearance and behaviour of woolly mammoth are among the best studied in Siberia and Alaska.

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The Coriolis Effect can be seen in action in the general circulation of the atmosphere. The winds at all latitudes to the north of 0° deflect to the right of their intended path in the Northern Hemisphere. The Coriolis Effect does not impact the wind speed, only the wind direction.

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3 years ago
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In Drosophila, the genes for withered wings (whd), smooth abdomen (sm) and speck body (sp) are located on chromosome 2 and are s
lesya692 [45]

Answer:

A) 47; B) 33; C) 272; D) 122

Explanation:

The three genes are linked.

The female with withered wings and a smooth abdomen has the genotype whd sm sp+/whd sm sp+.

The male with a speck body has the genotype whd+ sm+ sp/whd+ sm+ sp.

Both individuals are homozygous for all genes, so each of them only produces one type of gamete. The resulting F1 therefore has the genotype whd sm sp+/ whd+ sm+ sp, heterozygous for all genes and with a wild-type phenotype.

The females of the F1 were mated with homozygous recessive males (test cross): whd sm sp/whd sm sp.

<h3>A)</h3>

If we assume interference is 0, the probability of crossing over happening between the genes whd and sm is independent from the probability of crossing over happening between sm and sp.

The distance = frequency of recombination × 100, so the frequency of recombination (RF) between genes whd and sm is 0.305 and the RF between genes sm and sp is 0.155.

<u>The expected double crossover progeny among the 1000 offspring will be:</u>

RF whd-sm × RF sm-sp  × 1000 =

0.305  × 0.155 × 1000 = 47 individuals will be double crossover.

<h3>B)</h3>

Interference is 0.3

The interference is calculated as 1- coefficient of coincidence (cc).

cc = observed double crossover/expected double crossover

Therefore:

I = 1 - cc

cc = 1 - I

<u>cc = 0.7</u>

Observed DCO / 47 = 0.7

Observed DCO = 0.7  × 47

Observed DCO ≅ 33

<h3>C)</h3>

The parental gametes are whd sm sp+ and whd+ sm+ sp (the genotype of the F1 female is known).

Looking at them and at the gene map we can tell that the gametes that give rise to withered wings, speck body (whd sm+ sp) and smooth abdomen (whd+ sm sp+) phenotypes are the result of recombination occurring between genes whd and sm.

To calculate the expected number of individuals with those phenotypes among the 1000 progeny we need to determine the frequency of recombination between the genes whd and sm considering there's interference.

The distance whd-sm = RF x 100

The recombination frequency is the sum of the single crossover between whd and sm and the double crossovers.

The frequency of DCO is 33/1000=0.033.

Distance whd-sm/ 100 = SCOwhd-sm + DCO

0.305 - 0.033 = SCO whd-sm

<u>Frequency of SCO whd-sm= 0.272</u>

And the expected number of individuals with those phenotypes will be 0.272 x 1000 = 272.

<h3>D)</h3>

The gametes that originate the phenotypes withered wings, speck body, smooth abdomen (whd sm sp) and wild type (whd+ sm+ sp+) are the result of recombination between genes sm and sp.

Distance sm-sp/ 100 = SCOsm-sp + DCO

0.155 - 0.033 = SCOsm-sp

<u>Frequency of SCO sm-sp= 0.122</u>

And the expected number of individuals with those phenotypes will be 0.122 x 1000 = 122.

6 0
4 years ago
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Marina86 [1]
One of the plants in this grouping are chrysanthemums.
8 0
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The difference between a dominant trait and a recessive trait is that the dominant trait must have one copy of each from two different parent
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Hh is dominant because this is of a copy of each from two parents
A recessive trait must have two same copies coming from the same two parents
Example: HH
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true or false along with natural selection,genetic drift has profoundly affected the evolution of human traits throughout our sp
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Answer:

yes

Explanation:

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