Answer:
Step-by-step explanation:
In the model
Log (salary) = B0 + B1LSAT +B2GPA +B3log(libvol) +B4log(cost)+B5 rank+u
The hypothesis that rank has no effect on log (salary) is H0:B5 = 0. The estimated equation (now with standard errors) is
Log (salary) = 8.34 + .0047 LSAT + .248 GPA + .095 log(libvol)
(0.53) (.0040) (.090) (.033)
+ .038 log(cost) – .0033 rank
(.032) (.0003)
n = 136, R2 = .842.
The t statistic on rank is –11(i.e. 0.0033/0.0003), which is very significant. If rank decreases by 10 (which is a move up for a law school), median starting salary is predicted to increase by about 3.3%.
(ii) LSAT is not statistically significant (t statistic ≈1.18) but GPA is very significance (t statistic ≈2.76). The test for joint significance is moot given that GPA is so significant, but for completeness the F statistic is about 9.95 (with 2 and 130 df) and p-value ≈.0001.
It is undefined when the denominator is 0
Answer:
The car must drive at 108 km/h to cover the same journey.
Step-by-step explanation:
Given that:
Time taken by bus journey = 45 minutes = 
Speed of bus = 60 km/h
Distance of the journey = Speed * Time
Distance of the journey = 60 * 0.75 = 45 km
The car needs to cover 45 km in 25 minutes.
25 minutes = 
Distance = Speed * Time
45 = 
Speed = 
Speed = 108 km/h
Hence,
The car must drive at 108 km/h to cover the same journey.
Answer:
t to the sixth power equals 9
t=1.5
Step-by-step explanation:
