A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.
B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.
C) The probability the golfer got six holes-in-one during a single game is close to 0%.
<h2 /><h2><u>How to determine probabilities</u></h2>
Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:
- 1 - 0.12 = 0.88
- 0.88 ^ 17 = 0.1138
- 0.88 ^ 18 = 0.1001
Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.
- 0.88 ^ 18 - 0.12 ^ 2 = X
- 0.0857 = X
Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.
- 0.12 ^ 6 x 0.88 ^ 12 = X
- 0.0000000001 = X
Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.
Learn more about probabilities in brainly.com/question/25273534
Answer: we need to see the problem
Step-by-step explanation:
Answer:
bigger
Step-by-step explanation:
-3 is bigger then -12
Answer:
34
Step-by-step explanation:
The mean is calculated as
mean = 
let x be the missing frequency, then
Total frequency × midpoint
= (16 × 2) + 7x + (20 × 12) + (10 × 17) = 32 + 7x + 240 + 170 = 442 + 7x
Total frequency = 16 + x + 20 + 10 = 46 + x, thus
= 8.5 ( cross- multiply )
442 + 7x = 8.5(46 + x)
442 + 7x = 391 + 8.5x ( subtract 8.5x from both sides )
442 - 1.5x = 391 ( subtract 442 from both sides )
- 1.5x = - 51 ( divide both sides by - 1.5 )
x = 34
The missing frequency is 34
Hello, there!
If s = 9, then 2s = 2 * 9
2 * 9 = 18
2s = 18
I hope I helped!
Let me know if you need anything else!
~ Zoe
