1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ololo11 [35]
2 years ago
5

A sample of computer tablet batteries has a mean battery life of 28 months and standard deviation of 4 months. What is the lifes

pan of batteries that are within the given standard deviation of the mean?
1. 1 Standard deviation

2. 2 Standard deviation

3. 3 Standard deviation
Mathematics
1 answer:
Ulleksa [173]2 years ago
5 0

Using the Empirical Rule, it is found that the lifespans, in months, are given by:

1. 24 and 32.

2. 20 and 36.

3. 16 and 40.

<h3>What is the Empirical Rule?</h3>

It states that, for a normally distributed random variable:

  • Approximately 68% of the measures are within 1 standard deviation of the mean.
  • Approximately 95% of the measures are within 2 standard deviations of  the mean.
  • Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Hence, considering the mean of 28 months and the standard deviation of 4 months, the life spans are given by:

1. 24 and 32.

2. 20 and 36.

3. 16 and 40.

More can be learned about the Empirical Rule at brainly.com/question/24537145

You might be interested in
How many solutions does the system have?Explain
valkas [14]
There are NO SOLUTIONS.

Substitute the first equation for y in the second equation. You can see it does not work. 6 does not equal 8. Therefore there are no solutions.

6 0
3 years ago
I am the largest 7-digit number you can write with the digits 3, 6, 9, 4, 0, 8, and 2
nirvana33 [79]
9,864,320

Hope this helps, let me know if there's anything else I can help you with :)
5 0
4 years ago
Read 2 more answers
Here are the percents of the popular
kvv77 [185]

Answer: 57.4

Step-by-step explanation:

First order the numbers from the smallest to the largest:

49.6, 55.1, 57.4, 49.7, 61.1, 43.4,  60.7, 50.1, 50.7, 58.8, 53.9, 43.2,  49.2, 47.9, 51.2

to:

43.2, 43.4, 47.9, 49.2, 49.6, 49.7, 50.1, 50.7, 51.2, 53.9, 55.1, 57.4, 58.8, 60.7, 61.1.

The position of third quartile is:

= (N + 1) * 3/4

= (15 + 1) * 3/4

= 12th position

That number is:

= 57.4

8 0
3 years ago
Can somebody explain how these would be done? The selected answer is incorrect, and I was told "Nice try...express the product b
trapecia [35]

Answer:

Solution ( Second Attachment ) : - 2.017 + 0.656i

Solution ( First Attachment ) : 16.140 - 5.244i

Step-by-step explanation:

Second Attachment : The quotient of the two expressions would be the following,

6\left[\cos \left(\frac{2\pi }{5}\right)+i\sin \left(\frac{2\pi \:}{5}\right)\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

So if we want to determine this expression in standard complex form, we can first convert it into trigonometric form, then apply trivial identities. Either that, or we can straight away apply the following identities and substitute,

( 1 ) cos(x) = sin(π / 2 - x)

( 2 ) sin(x) = cos(π / 2 - x)

If cos(x) = sin(π / 2 - x), then cos(2π / 5) = sin(π / 2 - 2π / 5) = sin(π / 10). Respectively sin(2π / 5) = cos(π / 2 - 2π / 5) = cos(π / 10). Let's simplify sin(π / 10) and cos(π / 10) with two more identities,

( 1 ) \cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos \left(x\right)}{2}}

( 2 ) \sin \left(\frac{x}{2}\right)=\sqrt{\frac{1-\cos \left(x\right)}{2}}

These two identities makes sin(π / 10) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and cos(π / 10) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}.

Therefore cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}. Substitute,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

Remember that cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting those values,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right]

And now simplify this expression to receive our answer,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right] = -\frac{3\sqrt{5+\sqrt{5}}}{4}+\frac{3\sqrt{3-\sqrt{5}}}{4}i,

-\frac{3\sqrt{5+\sqrt{5}}}{4} = -2.01749\dots and \:\frac{3\sqrt{3-\sqrt{5}}}{4} = 0.65552\dots

= -2.01749+0.65552i

As you can see our solution is option c. - 2.01749 was rounded to - 2.017, and 0.65552 was rounded to 0.656.

________________________________________

First Attachment : We know from the previous problem that cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}, cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting we receive a simplified expression,

6\sqrt{5+\sqrt{5}}-6i\sqrt{3-\sqrt{5}}

We know that 6\sqrt{5+\sqrt{5}} = 16.13996\dots and -\:6\sqrt{3-\sqrt{5}} = -5.24419\dots . Therefore,

Solution : 16.13996 - 5.24419i

Which rounds to about option b.

7 0
3 years ago
How much pure acid should be mixed with 6 gallons of a 20% acid solution in order to get a 90% acid solution?
beks73 [17]
So, how much acid is there in 6 gallons?  well is 20% acid or (20/100), so the amount of acid in it just (20/100) * 6 or 1.2, the rest is say water.

now, if we want a 90% solution, and say we add "y" gallons, how much acid is in it?  well (90/100) * y, or 0.9y.

now let's add "x" gallons of pure acid, now, pure acid is just pure acid, so is 100% acid, how much acid is there in it?  (100/100) * x, or 1x or just x.

we know whatever "x" and "y" amounts are, they -> x + 6 = y

and we also know that x + 1.2 = 0.9y

\bf \begin{array}{lccclll}&#10;&\stackrel{gallons}{acid}&\stackrel{acid~\%}{quantity}&\stackrel{acid~gallons}{quantity}\\&#10;&------&------&------\\&#10;\textit{pure acid}&x&1.00&x\\&#10;\textit{20\% sol'n}&6&0.20&1.2\\&#10;------&------&------&------\\\&#10;mixture&y&0.90&0.9y&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;x+6=\boxed{y}\\&#10;x+1.2=0.9y\\&#10;----------\\&#10;x+1.2=0.9\left( \boxed{x+6} \right)&#10;\end{cases}&#10;\\\\\\&#10;x+1.2=0.9x+5.4\implies x-0.9x=5.4-1.2\implies 0.1x=4.2&#10;\\\\\\&#10;x=\cfrac{4.2}{0.1}\implies x=\stackrel{gallons}{42}
3 0
3 years ago
Other questions:
  • The sum of the first 6 terms of a geometric sequence is 7, 812. the common ratio is 5. what is the second term of the sequence?
    6·1 answer
  • PLSSS ANSWER QUICKLYYY!!!! Adrian loses $4, then earns $8. Did Adrian gain or lose overall?
    13·2 answers
  • Aurelio Espinoza buys a computer disk file for 14.95 , a surge protector for 19.95 and 2 boxes of labels for 19.99 each . The sa
    12·1 answer
  • A sphere has a radius of 3.5 centimeters.
    6·1 answer
  • PLEASE HELP ASAP
    9·1 answer
  • if there is a total volume of 5,090km3 of liquid surface fresh water, what volume is found in swamps?
    13·1 answer
  • Which expression is equivalent to 7(4+7)? *
    9·2 answers
  • Which relation is a function?
    13·2 answers
  • Write the equation of a line perpendicular to y=2x-5y=2x−5 that passes through the point (2, -5).
    14·1 answer
  • Solve −3(7n+3)&lt;6n. Write the solution using set-builder notation.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!