Answer:
(3×10^3)+(3×10^2)+(2×10^1)+(7×10^0)
Answer:
10, 5, 19
Step-by-step explanation:
Recall that
So we can multiply the fraction by
And get
<h3>
Answer:</h3>
- a_n = -3a_(n-1); a_1 = 2
- a_n = 2·(-3)^(n-1)
<h3>
Step-by-step explanation:</h3>
A) The problem statement tells you it is a geometric sequence, so you know each term is some multiple of the one before. The first terms of the sequence are given, so you know the first term. The common ratio (the multiplier of interest) is the ratio of the second term to the first (or any term to the one before), -6/2 = -3.
So, the recursive definition is ...
... a_1 = 2
... a_n = -3·a_(n-1)
B) The explicit formula is, in general, ...
... a_n = a_1 · r^(n -1)
where r is the common ratio and a_1 is the first term. Filling in the known values, this is ...
... a_n = 2·(-3)^(n-1)
9513 1404 393
Answer:
- changes by 120 for each copy
- is 1800 if none are sold
Step-by-step explanation:
Let's look at the second question first.
x is the number of copies Chau sells. If he doesn't sell any copies, then x = 0. To find Chau's pay, we use x=0 in the equation, and solve for y.
120×0 +1800 = y
0 +1800 = y
1800 = y
Chau's pay when he sells no copies is $1800.
__
If Chau sells 1 copy, then his pay is ...
120×1 +1800 = y = 1920 . . . . . . . use the equation with x = 1
The increase in Chau's pay is 1920 -1800 = 120.
Chau's pay changes by $120 for each copy he sells.
Answer:
- 5/7 - (3/14 + 3/14) = 2/7
See the steps of solution:
- 5/7 - (3/14 + 3/14) = Solve parenthesis first
- 5/7 - (3 + 3)/14 = Add fractions with same denominator
- 5/7 - 6/14 = Simplify
- 5/7 - 3/7 = Subtract fractions with same denominator
- (5 - 3)/7 = Simplify
- 2/7 Answer
