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3 years ago

Help plzzzz ill give extra points

Mathematics

2 answers:

Artyom0805 [142]3 years ago

7 0

<h3>Solution :-</h3>

Total equation ,

$\displaystyle\sf\to 4x+\boxed{\sf 12}x=\boxed{\sf 320}$

$\displaystyle\sf\to \boxed{\sf 16}x=\boxed{\sf 320}$

$\displaystyle\sf\to x =\boxed{\sf 20}$

lbvjy [14]3 years ago

3 0

Answer:

12x

16x, 320

Step-by-step explanation:

Hope this helps

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Is -31 >or equal to -3

strojnjashka [21]

Answer:

-3 is greater than -31

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3 years ago

Ok last question for today <br> Will mark brainliest

Pepsi [2]

Answer:9

Step-by-step explanation:

8 * 9 = 72

8, 16, 24, 32, 40, 48, 56, 64, 72

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3 0

3 years ago

Melia put the $30 her Grandmother gave her for her tenth birthday into her piggy bank. Each week after

Vladimir [108]

This is a sequence because the points form a straight line. The expression is: t(n) = 30 + 2x, x is number of weeks. On her 18th birthday, that is 8 years after her 10th. that means 416 weeks have passed since her 10th birthday. Plug 416 into the equation to get: t(416) = 30 + 2(416) = $862. She will have $862 to Spend.

3 0

3 years ago

A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic

stellarik [79]

Answer:

a) There is a 59.87% probability that none of the LED light bulbs are defective.

b) There is a 31.51% probability that exactly one of the light bulbs is defective.

c) There is a 98.84% probability that two or fewer of the LED light bulbs are defective.

d) There is a 100% probability that three or more of the LED light bulbs are not defective.

Step-by-step explanation:

For each light bulb, there are only two possible outcomes. Either it fails, or it does not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 10, p = 0.05$

a) None of the LED light bulbs are defective?

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}*(0.05)^{0}*(0.95)^{10} = 0.5987$

There is a 59.87% probability that none of the LED light bulbs are defective.

b) Exactly one of the LED light bulbs is defective?

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{10,1}*(0.05)^{1}*(0.95)^{9} = 0.3151$

There is a 31.51% probability that exactly one of the light bulbs is defective.

c) Two or fewer of the LED light bulbs are defective?

This is

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = 2) = C_{10,2}*(0.05)^{2}*(0.95)^{8} = 0.0746$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.5987 + 0.3151 + 0.0746 0.9884$

There is a 98.84% probability that two or fewer of the LED light bulbs are defective.

d) Three or more of the LED light bulbs are not defective?

Now we use p = 0.95.

Either two or fewer are not defective, or three or more are not defective. The sum of these probabilities is decimal 1.

$P(X \leq 2) + P(X \geq 3) = 1$

$P(X \geq 3) = 1 - P(X \leq 2)$

In which

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = 0) = C_{10,0}*(0.95)^{0}*(0.05)^{10}\cong 0$

$P(X = 1) = C_{10,1}*(0.95)^{1}*(0.05)^{9} \cong 0$

$P(X = 2) = C_{10,1}*(0.95)^{2}*(0.05)^{8} \cong 0$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0$

$P(X \geq 3) = 1 - P(X \leq 2) = 1$

There is a 100% probability that three or more of the LED light bulbs are not defective.

8 0

3 years ago

The length of a rectangle is 3 1/6 cm longer than the width. The perimeter of the rectangle is 15 1/3 cm. What are the width and

timofeeve [1]

Answer:

$Width = 2\frac{1}{4}cm$

$Length=5\frac{5}{12} cm$

Step-by-step explanation:

Data from the question;

Perimeter of a rectangle is $15\frac{1}{3}$ cm

Length is $3\frac{1}{6}$ cm longer than the width

We are supposed to determine the length and the with of the rectangle;

Assuming, the width x cm

Then, the length is $x+3\frac{1}{6}$ cm

We need to know that the perimeter of a rectangle is given by;

Perimeter = 2 ( length + width)

Therefore;

$15\frac{1}{3}= 2 ( x + (x+3\frac{1}{6}))$

$15\frac{1}{3}=2(2x+3\frac{1}{6})$

Thus;

$15\frac{1}{3}=4x+6\frac{1}{3}$

$4x=9\\x=2\frac{1}{4}$

Therefore;

$Width = 2\frac{1}{4}cm$

$Length = x + 3\frac{1}{6}$

$=2\frac{1}{4}+3\frac{1}{6}$

$=5\frac{5}{12} cm$

Therefore; the length is $5\frac{5}{12}$ cm while the width is $2\frac{1}{4}$ cm

7 0

3 years ago