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11111nata11111 [884]
3 years ago
5

If the composite functions f(g(x)) and g(f(x)) equal x then the function g is the __________ function of ff.

Mathematics
1 answer:
sdas [7]3 years ago
6 0
<span>If the composite functions f(g(x)) and g(f(x)) equal x then the function g is the __________ function of ff.

</span>inverse

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PLEASE HELP WILL GIVE BRAINLIEST!<br> y= 3x — 5<br><br> y=6x — 8<br> solve with elimination pls
Citrus2011 [14]

Answer:

Point form: (1,-2)

Equation form: x=1 y= -2

Step-by-step explanation:

Hope it helps

4 0
3 years ago
44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
3 years ago
While mining, Keith found a large metal bar that weighed 42 ounces. Keith was also able to determine that the bar had 30 ounces
Usimov [2.4K]
Divide the silver present in the bar by the total weight of the bar to find the percentage of silver in the bar.

30 / 42 = 0.7142

Multiply this decimal by 100 for the percentage.

.7142 * 100 = 71.42

Rounded to the nearest tenth, 71.4% of the weight of the bar is silver.
8 0
3 years ago
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