Answer:B
Step-by-step explanation:
The wallet was y’all doin was a good night I gotta have to be back in the time of my time with you again and daddy mommy daddy and daddy daddy and mommy daddy mommy mommy daddy and daddy mommy mommy and yyyyy
Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
Answer: 56 large cars and 86 small cars.
Step-by-step explanation:
Let's call:
: the number of large cars.
: the number of small cars.
Then, you can set up the following system of equations:
You can use the Elimination Method:
- Multiply the first equation by -4.0
- Add both equations.
- Solve for l.
≈
Substitute 
into one of the original equations and solve for <em>s:</em>
<em> </em>
