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2 years ago

Help me solve for 20 please ok?

Mathematics

1 answer:

Mashutka [201]2 years ago

8 0

Answer:

option c

Step-by-step explanation:

Quadratic function f(x) = ax² + bx +c

Here the the co-efficient of x, that is a tells if the graph is wider or narrower.

1) a < 1 that is if a is decimal less than 1, then the graph is wider.

2) a > 1, then the graph is narrow.

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Williams is six years younger than three times Alex's age Williams is 33 years old how old is Alex A 9 years old

Harrizon [31]

W = 3A - 6
W = 33

33 = 3A - 6
33 + 6 = 3A
39 = 3A
39/3 = A
13 = A.....he is 13

8 0

3 years ago

How, do you divide big numbers.

Triss [41]

Answer:

hope this helps! :)

Step-by-step explanation:

Partition the primary number of the profit (or the two first numbers if the past advance took another digit) by the principal digit of the divisor. Compose the consequence of this division in the space of the remainder. Increase the digit of the remainder by the divisor, compose the outcome underneath the profit and deduct it

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3 years ago

Read 2 more answers

Is the value of the fraction 7−2y/6 greater than the value of the fraction 3y−7/12 ?

Sveta_85 [38]

Complete Question:

Is the value of the fraction 7−2y/6 greater than the value of the fraction 3y−7/12 ? For what values?(Make sure to use an inequality)

Answer:

y < 3

Step-by-step explanation:

The given two fractions are:

$\frac{7-2y}{6}$ and $\frac{3y-7}{12}$

We have to tell for which range of values is the value of first fraction larger than the second fraction. This can be done by setting up an inequality as shown:

$\frac{7-2y}{6} >\frac{3y-7}{12}$

The range of y which will satisfy this inequality will result in first fraction of larger value as compared to the second fraction.

Multiplying both sides of inequality by 12, we get:

$12 \times \frac{7-2y}{6} > 12 \times \frac{3y-7}{12} \\\\ 2(7-2y)>3y-7\\\\ 14-4y>3y-7\\\\ 14+7>3y+4y\\\\ 21>7y\\\\ 3>y\\\\ y$

This means, for y lesser than 3, the value of first fraction is larger than the second one.

3 0

2 years ago

The pizza has an area of 78.5 in². What is the minimum width of a placemat that can be placed underneath it so that the pizza do

andrey2020 [161]

Answer:

Step-by-step explanation:

This problem bothers on the mensuration of flat shapes, circles and square.

we know that the pizza has a circular profile

and the place-mat has a square profile.

Step one:

let us solve for the radius of the pizza

$area-of- pizzza= \pi r^2\\\\ 78.5= 3.142*r^2\\\\r^2= 78.5/3.142\\\\r^2= 24.98\\\\r= \sqrt{24.98} \\\\r=4.998\\\\r= 5 in$

Step two:

from inspection we know that the width of the place-mat is same as the diameter of the pizza

hence diameter of pizza

= 2r

=2*5

=10 in

3 0

3 years ago

3 times as much as the sum of 3/4 and 2/6

sasho [114]

3 times as much as the sum of 3/4 and 2/6

4 0

2 years ago