All categories

3 years ago

What is the sum?

Mathematics

1 answer:

Alona [7]3 years ago

8 0

D.6x^2+3x+3, to find your answer combine like terms. ex: x^2 and 5x^2 have ^2 in common so combine to get 6x^2.

You might be interested in

Find the area of the trapezoid using the formula using the A=1/2h(b1+b2)

pentagon [3]

Answer:

9

Step-by-step explanation:

1/2 bh (b1+b2)
Count all the squares for the base (6 squares)
Half it bc 1/2bh, which is not 3(h)
Now count the amount of squares to the top of it from the bottom (3 as well)
Now the problem is 3(3) which is 9.
So, the answer is 9

Hope this helps! Comment on it if you need more explanation!:)

4 0

3 years ago

(05.02 LC)What is the area, in square inches, of the figure shown here? A parallelogram with a height of 4inches is shown. The h

antoniya [11.8K]

Answer:

36 in²

Step-by-step explanation:

The figure that is been described is a Parallelogram.

The area of a Parallelogram is = Base × Height

From the question, the Height of the Parallelogram = 4 inches

The Base of the Parallelogram is calculated as the Length or base of the rectangle + base of the triangle

= 5 inches + 4 inches

= 9 inches

Area of the Parallelogram = 9 inches × 4 inches

= 36 square inches or 36 in²

6 0

3 years ago

Grace’s catering company receives an order for 118 Apple pies. Grace used 8 Apples to make one apple pie. How many apples does s

luda_lava [24]

Tha answer is 15 apple pies. Divide 118 pies by 8 apples. You will get 14 and a remainder. Add one more to the quotient.

5 0

3 years ago

Read 2 more answers

A mirror is the shape of an ellipse defined by y^2/7.29 + x^2/6.25 = 1 with units in feet. Which statement identifies the

hodyreva [135]

Answer:

The mirror has a vertical orientation and is 5.4 ft tall.

Step-by-step explanation:

Took the test

4 0

3 years ago

Read 2 more answers

Brahmagupta’s solution to a quadratic equation of the form ax2 + bx = c involved only one solution. Which solution would he have

sineoko [7]

Answer:

$\text{The solution is }\frac{\sqrt{88}-4}{6}$

Step-by-step explanation:

Given that Brahmagupta’s solution to a quadratic equation of the form

$ax^2+bx=c$ involved only one solution.

we have to find the solution for the equation

$3x^2 + 4x = 6$

$\text{The solution for the equation }ax^2+bx=c$ is

$x=\frac{\sqrt{4ac+b^2}-b}{2a}$

$\text{The solution for the equation }3x^2+4x=6$ is

$x=\frac{\sqrt{4(3)(6)+4^2}-4}{2(3)}$

$x=\frac{\sqrt{72+16}-4}{6}$

$x=\frac{\sqrt{88}-4}{6}$

7 0

3 years ago

Read 2 more answers