Answer:
The time interval when
is at 
The distance is 106.109 m
Step-by-step explanation:
The velocity of the second particle Q moving along the x-axis is :

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.
We are also to that :
between 
The schematic free body graphical representation of the above illustration was attached in the file below and the point when
is at 4 is obtained in the parabolic curve.
So,
is at 
Taking the integral of the time interval in order to determine the distance; we have:
distance = 
= 
= By using the Scientific calculator notation;
distance = 106.109 m
Hello!
We know that the length of the pack is 8 cm, width is 2 cm, and the volume is 48 cm^3.
The formula for volume is:
V = l × w × h
We don't want to find the volume...we already have that!
But we can use the volume and the length and width to find the height.
Since we multiply the dimensions to find the volume, we'll have to do the opposite to find a dimension.
And what's the opposite of multiplication? Division!
H = V ÷ lw
Multiply the length by the width, then divide the volume by that.
H = 48 ÷ 8(2)
H = 48 ÷ 16
H = 3
We can double check by using this to find the volume.
V = 8 × 2 × 3
V = 48
This means we're right!
ANSWER:
The height of the pack of gum is 3 centimetres.
Answer:
c) assets, liabilities, and owner's equity
Step-by-step explanation:
Answer: 16 minutes
30-27. 28 = 2. 72
2. 72 ÷ 0. 17 = 16
Take out a GCF (greatest common factor, which is 3x) factor what is left, (x^2 - 4)
Please respond if you understand, or if you need more help!