Answer:
Below in bold
Step-by-step explanation:
I AM ASSUMING that CDEF is a Rhombus.
If it is than triangle DEG is right-angled.
so 2x + 18 + 5x + 2 = 90.
7x = 90 - 20 = 70
x = 7.
So m < CDF = 5x + 2
= 5(10) + 2
= 52 degrees.
m < DCE = 2(10) + 18 = 38 degrees.
The diagonal bisects < DCF so m < ECF = 38 degrees.
So m < DCF = 2 * 38 = 76 degrees.
Opposite angles of a rhombus are equal so m < DEF = 76 degrees.
Answer:
0.67449
Step-by-step explanation:
Let be the 3rd quartile of normal distribution .
-z-score corresponding to the upper quartile can be calculated in excel as:
- In Excel, click on any empty cell'
- Type the function NORMINV
- Enter the probability as 0.75, mean= 0 and standard deviation=1
- Click the enter button.
-The output is 0.67449. Hence, the z-score corresponding to the upper quartile (Q3) of a normal distribution is 0.67499
210 = b(14)
210/14 = b
<span>15 square feet = b (base area)</span>
A=p (1+I/k)^kn
A future value 160000
p present value ?
I interest rate 6/100=0.06
K compounded semiannual 2
T time 18-7=11years
160000=p (1+0.06/2)^(2×11)
Divide each side by (1+0.06/2)^(2×11)
P=160,000÷(1+0.06÷2)^(2×11)
P=83,502.8
Hope it helps:-)