First three common multiples of 4 5 and 10

Mathematics

1 answer:

Lapatulllka [165]3 years ago

8 0

20 40 60 these are the first three

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How to solve 9x-7y=-7

frutty [35]

first lets solve for x
9x-7y=-7
it will be easier to start if the equation is equal to 0
so first add 7 on both sides
9x-7y=-7
+7 +7
now we have
9x-7y+7=0
now to get x on one side subtract 9x from both sides
 9x-7y+7=0
-9x -9x
--------------------
-7y+7=-9x
now to get x alone we divide both sides by -9
7/9y-7/9=x

7 0

4 years ago

Lynne invested 35,000 into an account earning 4% annual interest compounded quarterly she makes no other deposits into the accou

storchak [24]

Hello!

Lynne invested 35,000 into an account earning 4% annual interest compounded quarterly she makes no other deposits into the account and does not withdraw any money. What is the balance of Lynne's account in 5years

Data:

P = 35000

r = 4% = 0,04

n = 4

t = 5

P' = ?

I = ?

We have the following compound interest formula

$P' = P*(1+\dfrac{r}{n})^{nt}$

$P' = 35000*(1+\frac{0,04}{4})^{4*5}$

$P' = 35000*(1+0,01)^{20}$

$P' = 35000*(1,01)^{20}$

$P' = 35000*(1.22019003995...)$

$P' \approx 42,706.66$

So the new principal P' after 5 years is approximately $42,706.66.

Subtracting the original principal from this amount gives the amount of interest received:

$P' - P = I$

$42,706.66 - 35000 = \boxed{\boxed{7,706.66}}\end{array}}\qquad\checkmark$

________________________

I Hope this helps, greetings ... Dexteright02! =)

4 0

3 years ago

Andrea recorded the points she scored in her last eight basketball games. What is the mean absolute deviation of the scores

grandymaker [24]

The mean absolute deviation is a measure of variability in statistics. This number tells us how close the rest of the numbers are to the mean. The closer they are to the mean, the more reliable the data is.

The attached work shows how to find the MAD (mean absolute deviation).

Here are the steps:
1. Find the mean of the data. 2. Find the difference between the mean and the data values. 3. Find the average of these differences.