A new youth sports center is being built in a safe harbor. The perimeter of the rectangular playing field is 510 yards. The leng
th is the field is 5 yards less than quadruple the width. What are the dimensions of the plying field?
1 answer:
Answer:
<h2>L=203 yards</h2><h2>W=52 yards</h2>
Step-by-step explanation:
Step one:
given data
perimeter= 510 yards
let the width be x, width=x
length= (4x-5)-----quadruple mean 4 times
Step two:
the expression for perimeter is
P=2L+2W
510=2(4x-5)+2x
510=8x-10+2x
510+10=8x+2x
520=10x
divide both sides by 10
x=520/10
x=52
the width is 52 yards
the lenght is (4x-5)
L=4(52)-5
L=208-5
L=203 yards
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