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SVEN [57.7K]
3 years ago
7

A new youth sports center is being built in a safe harbor. The perimeter of the rectangular playing field is 510 yards. The leng

th is the field is 5 yards less than quadruple the width. What are the dimensions of the plying field?
Mathematics
1 answer:
podryga [215]3 years ago
4 0

Answer:

<h2>L=203 yards</h2><h2>W=52 yards</h2>

Step-by-step explanation:

Step one:

given data

perimeter= 510 yards

let the width be x, width=x

length= (4x-5)-----quadruple mean 4 times

Step two:

the expression for perimeter is

P=2L+2W

510=2(4x-5)+2x

510=8x-10+2x

510+10=8x+2x

520=10x

divide both sides by 10

x=520/10

x=52

the width is 52 yards

the lenght is  (4x-5)

L=4(52)-5

L=208-5

L=203 yards

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