Question

...........................

Answer 1

Answer:

It’s just a black screen I cant see the picture?

Answer 2

Answer:

1.

It has two solution because it is in quadratic form.

2.

(x-4)²-28=8

x²-8x+16-28-8=0

x²-8x-20=0

Doing middle term factorization

x²-(10-2)x-20=0

x²-10x+2x-20=0

x(x-10)+2(x-10)

(x-10)(x+2)=0

either

x=10

or

x=-2

:. x= 10 or -2

3.

2x²-5x-5=0

Comparing above equation with ax²+bx +c

we get

a=2

b=-5

c=-5

quadratic equation is

$x = \frac{ - b ± \sqrt{ {b}^{2} - 4ac} }{2a}$

Substituting value

$x = \frac{ 5 ± \sqrt{ {-5}^{2} - 4×2×-5} }{2×-5}$

-10x=5±$\sqrt{ {25+ 40}}$

taking + ve

-10x=5+$\sqrt{ {65}}$

x=-½-$\frac {\sqrt{ {65}}}{10}$

taking -ve

x=-½+$\frac {\sqrt{ {65}}}{10}$