Answer:
-9/4
Step-by-step explanation:
putting these to y/x form it is 9/-10 and -9/-6 which has a difference of -9/4 (hopefully this is correct-)
Answer:
If I'm guessing, you're supposed to write an equation. So the answer would be yx + 12y.
Step-by-step explanation:
Answer:
1.76% probability that in one hour more than 5 clients arrive
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given time interval.
The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per hour.
This means that 
What is the probability that in one hour more than 5 clients arrive
Either 5 or less clients arrive, or more than 5 do. The sum of the probabilities of these events is decimal 1. So

We want P(X > 5). So

In which










1.76% probability that in one hour more than 5 clients arrive
it would be the third one, 2/3
So, let's first focus on the first year:
the population then would be: 23000* (100+2)%
100% is the old population the 2% is the incease, so in total it's 102%, or 1.02 - the same number written differently.
So it will be 23000*1.02
After two years it will be 23000*1.02*1.02, and so on
so after x years it will be:
y=23000*