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3 years ago

I’m not sure if I’m right but can someone help.!

Mathematics

2 answers:

loris [4]3 years ago

6 0

Answer:

4/9

Step-by-step explanation:

because it is 0.44444444 repeating :)

Ivahew [28]3 years ago

6 0

Answer:

I think this is right. I checked with my mom, a math wiz, and she says its 11/25. But that can't be simplified, and its not an option. Try simplifying the fraction 11/25.. Hope it helps

Step-by-step explanation:

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Solve for x: 1/2x + 4 = 9

Artist 52 [7]

Answer:

2 1/2 or 2.5

Step-by-step explanation:

1/2x +4=9

-4 -4

1/2x= 5

/1/2 /1/2

x= 2 1/2 or 2.5

7 0

4 years ago

A tractor costs $12,250 and depreciates in value by 6% per year. How much will the tractor be worth in 6 years?

GaryK [48]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

If g(x)=x+1/x-2 and h(x)=4-x,what is the value of (g.h)(-3)?

dlinn [17]

Answer:

$g.h(-3) = \frac{14}{5}$

Step-by-step explanation:

We are given these following functions:

$g(x) = \frac{x + 1}{x - 2}$

$h(x) = 4 - x$

Multiplication function:

$g.h(x) = \frac{x + 1}{x - 2} \times (4 - x) = \frac{(x+1)(4-x)}{x - 2}$

At x = -3

$g.h(-3) = \frac{(-3+1)(4-(-3))}{-3 - 2} = \frac{(-2)(7)}{-5} = \frac{-14}{-5} = \frac{14}{5}$

$g.h(-3) = \frac{14}{5}$

8 0

3 years ago

What is the sum of the first eight terms of the geometric series 2 + 6 + 18 + 54 + … ?

UkoKoshka [18]

2+6+18+54+162+486+1458+4375=6561

you multiply the previous number by three to find the next value

7 0

3 years ago

What is the range of the function f(x) = (x + 3)2 + 4?

Tju [1.3M]

Range of $f(x)=(x + 3)^2 + 4$ is [4,∞).

<u>Step-by-step explanation:</u>

Here we have , function $f(x)=(x + 3)^2 + 4$ , We need to find range of this function . Let's find out:

In the function $f(x)=(x + 3)^2 + 4$ , Let's focus on $(x+3)^2$ : It's a perfect square whose value will be always positive and greater then equal to zero i.e.

⇒ $(x+3)^2\geq 0$ , So minimum value of $(x+3)^2$ is 0 at x=-3 . ∴

⇒ $f(x)=(x + 3)^2 + 4$

⇒ $f(-3)=(-3+ 3)^2 + 4$

⇒ $f(-3)= 4$

Minimum value of $f(x)=(x + 3)^2 + 4$ is 4 , And maximum value of $f(x)=(x + 3)^2 + 4$ can be ∞ as value of x can be increased . Therefore , Range of $f(x)=(x + 3)^2 + 4$ is [4,∞).

7 0

4 years ago