Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
Answer:
A) 14x + 2
Step-by-step explanation:
(2x + 2x) + (5x + 5x) + (1 + 1)
= 4x + 10x + 2
= 14x + 2
You can only add 4x and 10x since they both have a variable (x). You cannot add 2 since 2 doesn't have a variable, so the answer in simplest form is 14x + 2
Answer:
y = (x + 9)² -93
vertex: (-9, -93)
Step-by-step explanation:
x² + 18x = 12
x² + 18x + 81 = 12 + 81
(x+9)² = 93
y = (x + 9)² -93
vertex: (-9, -93)
