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Elanso [62]
3 years ago
13

Solve for the given variable

Mathematics
1 answer:
Aleks04 [339]3 years ago
7 0

Answer:

42 degrees

Step-by-step explanation:

Angles in a triangle equal 180

180-(37+90)=53

Angles on a line equal 180

180-53=127

127=3b+1

126=3b

b=42

42 degrees

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Solve the equation. 1/3a = -5​
djyliett [7]

Answer:

The answer is a = -15

Step-by-step explanation:

1/3a = -5

3 × 1/3a = 3 × (-5)

a = 3 × (-5)

a = -3 × 5

Answer is a = -15

3 0
3 years ago
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Pls help me with this :)<br><br><br> .
san4es73 [151]

Answer:

35 is the answer thank u 35 is a real answer

3 0
3 years ago
I need help remembering the steps to solve
Viefleur [7K]
Take a common point ( C in this case)
1. Take the difference of the y coordinates from the point vertical to C.
   C from D in this case.
2.Take the diff of the x coordinates from the points  horizontal to the first.
  C from B in this case.
3. Now add the diff to the common point. X to x Y to y.
 
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3 years ago
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Which statement about the simplified binomial expansion of (a + b)", where n is a positive integer, is true?
Alja [10]

Answer:

(a+b)^n  ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + .....  +{n \choose n}a^{(0)}b^{(n)}

Step-by-step explanation:

The Given question is INCOMPLETE as the statements are not provided.

Now, let us try and solve the given expression here:

The given expression is: (a +b)^n, n > 0

Now, the BINOMIAL EXPANSION is the expansion which  describes the algebraic expansion of powers of a binomial.

Here, (a+b)^n  = \sum_{k=0}^{n}{n \choose k}a^{(n-k)}b^{(k)}

or, on simplification, the terms of the expansion are:

(a+b)^n  ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + .....  +{n \choose n}a^{(0)}b^{(n)}

The above statement holds for each  n > 0

Hence, the complete expansion for the given expression is given as above.

4 0
3 years ago
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I ready scientific notation help
Airida [17]

The required value is 2\times10^9

Step-by-step explanation:

Weight of ants = 4\times10^{-3}

Weight of elephant= 8\times10^6

We need to find, the total weight of about how many ants equals to the weight of an oversized elephant.

The equation given is:

4\times10^{-3} \times a = 8\times10^6

We need to find a:

Solving:

4\times10^{-3} \times a = 8\times10^6\\a=\frac{8\times10^6}{4\times10^{-3}}\\if \,\,10^a/10^-b \,\,then\,\, 10^{a+b}\\a=2\times10^{6+3} \\a=2\times10^9

So, the required value is 2\times10^9

Keywords: Scientific Notation

Learn more about Scientific Notation at:

  • brainly.com/question/11984920
  • brainly.com/question/5565320
  • brainly.com/question/5756316

#learnwithBrainly

4 0
3 years ago
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