Solve for the given variable
1 answer:
You might be interested in
The 99% confidence interval for the population proportion is given by
Given that 52% = 0.52 is the standard proportion and the standard error is 2.4% = 0.024.
Therefore, the <span>99% confidence interval for the fraction of u.s. adult twitter users who get some news on twitter is given by
</span>Therefore, the <span>99% confidence interval for the fraction of u.s. adult twitter users who get some news on twitter is 45.82% and 58.18%.
The interpretation of the confidence interval</span> is as follows: "We are 99% confident that the fraction of U.S. adult twiter users who get some news on twitter is between 45.82% and 58.18%.
Given that 52% = 0.52 is the standard proportion and the standard error is 2.4% = 0.024.
Therefore, the <span>99% confidence interval for the fraction of u.s. adult twitter users who get some news on twitter is given by
</span>Therefore, the <span>99% confidence interval for the fraction of u.s. adult twitter users who get some news on twitter is 45.82% and 58.18%.
The interpretation of the confidence interval</span> is as follows: "We are 99% confident that the fraction of U.S. adult twiter users who get some news on twitter is between 45.82% and 58.18%.