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3 years ago

5

What is the value of m that makes the equation true? 18m- 2+ 7m- 8= -60

1 answer:

sergij07 [2.7K]3 years ago

3 0

Answer:

m = -2

Step-by-step explanation:

First, let's move all variables to one side of the equation. (Don't forget to change the signs when you move the numbers to the other side.)

18m + 7m = -60 + 2 + 8

Now we simplify to get this:

25m = -50

Now we divide -50 by 25 which gets us -2.

Therefore, m = -2

Hope this helps!

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3, 12, 48, 192, 768, . . .

Sav [38]

The answer would be the sequence has a common ratio of 4.
The explanation for this would be:
To get the common ratio for get the simplest form of the two numbers, so 12/3 = 4 and 48/12 = 4So we know that their common ratio is 4.
To check:
3 x 4 = 12
12 x 4 = 48
48 x 4 = 192
192 x 4 = 768

7 0

3 years ago

Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points

$(2,1)\rightarrow (2,-1);$
$(1,2)\rightarrow (1,0);$
$(2,3)\rightarrow (2,1);$
$(3,2)\rightarrow (3,0).$

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

$(2,-1)\rightarrow (2,3);$
$(1,0)\rightarrow (1,2);$
$(2,1)\rightarrow (2,1);$
$(3,0)\rightarrow (3,2)$

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation $(x+2,y-0)$ will map vertices of the square into points

$(2,1)\rightarrow (4,1);$
$(1,2)\rightarrow (3,2);$
$(2,3)\rightarrow (4,3);$
$(3,2)\rightarrow (5,2).$

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

$(4,1)\rightarrow (2,1);$
$(3,2)\rightarrow (3,2);$
$(4,3)\rightarrow (2,3);$
$(5,2)\rightarrow (1,2)$

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation $(x+3,y+3)$ will map vertices of the square into points

$(2,1)\rightarrow (5,4);$
$(1,2)\rightarrow (4,5);$
$(2,3)\rightarrow (5,6);$
$(3,2)\rightarrow (6,5).$

2nd transformation = reflection over y = -x + 7 will map vertices into points

$(5,4)\rightarrow (3,2);$
$(4,5)\rightarrow (2,3);$
$(5,6)\rightarrow (1,2);$
$(6,5)\rightarrow (2,1)$

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation $(x-3,y-3)$ will map vertices of the square into points

$(2,1)\rightarrow (-1,-2);$
$(1,2)\rightarrow (-2,-1);$
$(2,3)\rightarrow (-1,0);$
$(3,2)\rightarrow (0,-1).$

2nd transformation = reflection over y = -x + 2 will map vertices into points

$(-1,-2)\rightarrow (4,3);$
$(-2,-1)\rightarrow (3,4);$
$(-1,0)\rightarrow (2,3);$
$(0,-1)\rightarrow (3,2)$

These points are not the vertices of the initial square.

5 0

3 years ago

What are the solutions of ×^2=8-5×?

yaroslaw [1]

Answer:

x=8 & x=3

Step-by-step explanation:

We want to get the (x)s all on one side.

add 5x to each side

${x}^{2} + 5x = 8$

Since x^2 is x•x and 5x is 5•x then we can change the formula to

x(x+5)=8

then seperate that

x=8

x+5=8

subtract 5 from each side

x=3.

The solutions are 8 and 3.

7 0

3 years ago

Find the area of the parallelogram shown below and choose the appropriate result.

Lisa [10]

Answer:

The area of the parallelogram is 0.1875 mile² ⇒ D

Step-by-step explanation:

The formula of the area of a parallelogram is A = b1 × h1 = b2 × h2, where

b1 and b2 are two adjacent sides of it

h1 and h2 are the heights perpendicular to these bases

In the given figure

∵ There is a parallelogram

∵ One of its bases is 0.25 mile

∴ b1 = 0.25 mile

∵ the height of this base is 0.75 mile

∴ h1 = 0.75 mile

→ By using the rule of the area above

∴ The area of the parallelogram = 0.25 × 0.75

∴ The area of the parallelogram = 0.1875 mile²

∴ The area of the parallelogram is 0.1875 mile²

6 0

2 years ago

How would you do number 8?

Aloiza [94]

Answer:

9^2

so it is (m+9)^2

Step-by-step explanation:

i guess that is the correct answer

4 0

3 years ago