I'm supposed to solve it orr?
Answer: Correct two digit number= 24
Step-by-step explanation:
Let
x= tens digit (wrong one)
and y= zeroes digit
and z= tens digit (right one)
Now according to the statement,
(10x+y)² - (10z+y)² = 2340
Simplifying this we get
(x-z)(5x+y+5z)= 117= 1 * 3 * 3 * 13
So it could either be
x-z=1 or x-z=3
If we take the x-z=1
then 5x+y+5z=117
which is not possible as maximum value we can get from this is 99.
This leaves us with x-z=3
so 5x+y+5z= 39
Put x=3+z
We get,
y+10z= 24
Now as y and z both are single digits so the only possible numbers to fit these are y=4 and z=2.
Put z=2 in x=3+z , we get x=5
So the numbers become 10x+y= 54
and 10z+y= 24
Their sum is 54+24=78
Check
54²-24²= 2340 so it is correct.
This is how I would work it out:
1st no. = x+1 2x+10=3(x+1)-7
2nd no. = x 2x+10=3x-4
x=14
1st no. is 15; 2nd no. is 14
To check: 28+10=38; three times the larger is 45; and 38 is 7 less than 45.
Answer:
40 students picked bananas
Step-by-step explanation:
3/4 picked apples
1 - 3/4 = 1/4 picked bananas
3/4x = 120
Multiply both sides of the equation by 4/3
4/3 * (3/4x) = 120/1 * (4/3)
x = 480/3
x = 160
Total of 160 students
/ \
120 = apples 160 - 120 = 40 = bananas
40 students picked bananas
Hope this helps :)
216. hope this helps you.
