We need Pythagoras theorem here
a^2+b^2 = c^2
a, b = legs of a right-triangle
c = length of hypotenuse
Let S=shorter leg, in cm, then longer leg=S+2 cm
use Pythagoras theorem
S^2+(S+2)^2 = (10 cm)^2
expand (S+2)^2
S^2 + S^2+4S+4 = 100 cm^2 [collect terms and isolate]
2S^2+4S = 100-4 = 96 cm^2
simplify and form standard form of quadratic
S^2+2S-48=0
Solve by factoring
(S+8)(S-6) = 0 means (S+8)=0, S=-8
or (S-6)=0, S=6
Reject nengative root, so
Shorter leg = 6 cm
Longer leg = 6+2 cm = 8 cm
Hypotenuse (given) = 10 cm
Answer:
answer is 10
Step-by-step explanation:
Thank you for posting your question here. Please see below answers for the problem above:
a. to find the circumference of the tire you need to multiply 3.14 by 2.5:
= 3.14 x 2.5
= 7.85 to round of it will be 8
b. to get the number of times the tire have to rotate to travel 1 mile:
1 mile = 5,280 ft
1 rotation is 7.85
5,280/7.85 = 672.611465
Answer:
Step-by-step explanation:
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