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serious [3.7K]
3 years ago
9

Write all the factors of 9 . Use commas to separate them.rtth

Mathematics
2 answers:
aliina [53]3 years ago
7 0

Answer:

1,3,9

Step-by-step explanation:

Rasek [7]3 years ago
5 0

Answer:

1, 3, 9

Step-by-step explanation:

the nine can be divided by those three numbers and no more

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Help???? i will be so greatfull
Stolb23 [73]
I 150
ii 200
iii 350
i 50
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7 0
3 years ago
Concrete is made by mixing screenings cement and sand in the ratio 3:1:15. How much sand would be needed to make 125 tons of con
alekssr [168]

Answer:

=    98.7 tons

Step-by-step explanation:

ratio =   3:1:15

amount of sand needed =    (15/19)*125      /  3 + 1 +15  =19

7 0
3 years ago
A building is in the shape of a square pyramid. Each side of the base is 54 meters long and the height is 260 meters.
choli [55]
Side of the base of the pyramid: s=54 m
Height of the pyramid: h=260 m
Volumen of the building = Volumen of the pyramid = V=?

V=Ab*h/3

Area of the base = Area of a square = Ab=s^2=(54 m)^2→Ab=2,916 m^2

V=(2,916 m^2)*(260 m)/3→V=252,720 <span>m³

Answer: T</span>he volume of the building is 252,720 m³
5 0
4 years ago
following frequency distribution shows the daily expenditure on milk of 30 households in a locality:Daily expenditure on milk(in
valina [46]

<em>Note:</em> <em>As you missed to identify what we have to find in this question. But, after a little research, I am able to find that we had to find the Mode for the data given in your question. So, I am assuming we have to calculate the the Mode. Hopefully, it would clear your concept regarding this topic.</em>

Answer:

The mode of the data = 75

Step-by-step explanation:

Lets visualize the given data in a table to show the frequency distribution:

<em>Daily expenditure on milk (in Rs)           Number of households</em>

<em>                  0-30                                                           5</em>

<em>                 30-60                                                          6        </em>

<em>                 60-90                                                          9</em>

<em>                 90-120                                                         6</em>

<em>                 120-150                                                        4</em>

Here the maximum frequency is 9.

So, modal class is <em>60-90.</em>

<em />

As the formula to calculate the mode:

Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )

Here, the maximum

l_{1} =60, f_{1} =9, f_{0}=6, f_{0}=6, h=30

l= is the lower limit of the class

f_{1} = is the frequency of the modal class

f_{0} = is the frequency of the previous modal class

f_{2} = is the frequency of the next previous modal class

l= is the class size

So,

Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )

Mode = 60 + 30 (\frac{9-6}{2(9)-6-6} )

Mode = 60 + \frac{(30)(3)}{6}

Mode = 60 + 15=75

∴ The mode of the data = 75

<em>Keywords: mode, frequency distribution</em>

<em> Learn more about mode and frequency distribution from brainly.com/question/14354368</em>

<em> #learnwithBrainly </em>

5 0
3 years ago
Find the value of x using trig please .....
iren [92.7K]

Answer:

8.090169944 or rounded 8.1

Step-by-step explanation:

Use SOH CAH TOA

Look at x and where it is and what you have.

First thing is to get an angle to use, 36, then to set up your equation.

___(36)=___

Figure out what you have.

You have the hypotonouse, 10, and need the adjacent,x, so you use the equation that involves H for hypotonouse and A for adjacent.

You set up your equation using COS, as you are using CAH.

Cos(36)=x/10

X is over ten sure to CAH C-cos A-adjacent and H-hypotonouse

Switch it around to make it equal to x

10*Cos(36)=x

You input it into your calculator. [10] [COS] [36] [ENTER] and you get the answer.

Round however is needed.

7 0
3 years ago
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