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deff fn [24]
3 years ago
6

Show the work for 3-(-4)

Mathematics
1 answer:
notka56 [123]3 years ago
5 0
It is;
3-(-4)
3- -4
3+4
7
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William bought some tickets to see his favorite singer. He bought some adult tickets and some children tickets, for a total of 1
Viefleur [7K]
Hello!

Let 'a' stand for adult tickets and 'c' for children tickets.

a + c = 15

(Both adult and children tickets make up a total of 15 tickets).

30a + 20c = 330

a = 3

c = 12

A N S W E R:

William bought 3 adults tickets and 12 children's tickets.

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3 years ago
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Ratio of 2:3 white flour to whole wheat flour to total of 10 cups flour
LenaWriter [7]
White flour makes up 2 / (2+3) of the total 10 cups:  2/5 of the total 10 cups.

2/5 times 10 is 4 cups.

You'll need 4 cups white flour and 6 cups whole wheat flour, making a total of 10 cups of flour.
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In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes
ale4655 [162]

Answer:

The sample mean is \bar{x}=14.371 min.

The sample standard deviation is \sigma = 18.889 min.

Step-by-step explanation:

We have the following data set:

\begin{array}{cccccccc}0.15&0.82&0.81&1.44&2.70&3.28&4.00&4.70\\4.96&6.49&7.25&8.03&8.40&12.15&31.89&32.47\\33.79&36.80&72.92&&&&&\end{array}

The mean of a data set is commonly known as the average. You find the mean by taking the sum of all the data values and dividing that sum by the total number of data values.

The formula for the mean of a sample is

\bar{x} = \frac{{\sum}x}{n}

where, n is the number of values in the data set.

\bar{x}=\frac{0.15+0.82+0.81+1.44+2.7+3.28+4+4.7+4.96+6.49+7.25+8.03+8.4+12.15+31.89+32.47+33.79+36.80+72.92}{19}\\\\\bar{x}=14.371

The standard deviation measures how close the set of data is to the mean value of the data set. If data set have high standard deviation than the values are spread out very much. If data set have small standard deviation the data points are very close to the mean.

To find standard deviation we use the following formula

\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }

The mean of a sample is  \bar{x}=14.371.

Create the below table.

Find the sum of numbers in the last column to get.

\sum{\left(x_i - \overline{X}\right)^2} = 6422.0982

\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 6422.0982 }{ 19 - 1} } \approx 18.889

7 0
3 years ago
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