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Elodia [21]
3 years ago
7

What is the value of x? The square root of 2x =4

Mathematics
2 answers:
VLD [36.1K]3 years ago
5 0

The answer would be: x=8

Here’s how you solve it!

\sqrt{2x} = 4

Square both sides to get 2x out of the square root. 4 squared is 16

2x=16

Then divide both sides by 2

X=8

Make sure to check your answer by adding the square root 2*8 =4

\sqrt{2 * 8} = 4

Then simplify and you get 4=4

Since 4=4 that means the answer is correct and you are left with your answer:

x=8

Hope this helps! :3

aleksklad [387]3 years ago
4 0
The answer is x=2
2x=4 divide both sides by 2
2x\2=4/2
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One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second
algol13

Answer:

Therefore the third container contains   \frac{735}{17}\% = 43.23 %  acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

= (V\times \frac{100+55}{100})   cubic unit.

=\frac{155}{100}V  cubic unit.

The amount of acid in first container is

=V\times \frac{25}{100}  cubic unit.

=\frac{25}{100}V  cubic unit.

The amount of acid in second container is

=(\frac{155}{100}V \times \frac{55}{100}) cubic unit.

=\frac{8525}{10000}V cubic unit.

Total amount of acid =(\frac{25}{100}V+\frac{8525}{10000}V) cubic unit.

                                   =(\frac{2500+8525}{10000}V) cubic unit.

                                   =(\frac{11025}{10000}V)cubic unit.

Total volume of mixture =(V+\frac{155}{100}V) cubic unit.

                                       =\frac{100+155}{100}V cubic unit.

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The amount of acid in the mixture is

=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%

=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%

=\frac{735}{17}\%

Therefore the third container contains  \frac{735}{17}\%  acid.

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