What is the equation that the line goes through (1,-2) and is parallel to y=3x-3?

Mathematics

1 answer:

scZoUnD [109]2 years ago

5 0

Answer:

Step-by-step explanation:

Parallel lines have the same slope.

Point-slope equation for line of slope 3 that passes through (1,-2):

y+2 = 3(x-1)

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What is the arc length of an arc with radius 10 in and central angle 60 degrees ? Show your work.

emmasim [6.3K]

Answer:

$\huge \boxed{ \boxed{ \red{{s \approx \: 10.47}}}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

geometry
PEMDAS

<h3>tips and formulas:</h3>

$s = \frac{\pi {r} \theta}{180}$

<h3>given:</h3>

r=10
$\theta = 60$

<h3>let's solve:</h3>

$\sf sustitute \: the \: value s \: of \: \theta \: and \: r : \\ =\frac{\pi \times 10 \times 60}{180}$
$\sf rediuce \: 60 : \\ =\frac{\pi \times 10 \times \cancel{60} \: ^{1} }{ \cancel{180} \: \:^{3} } \\ =\frac{\pi \times 10}{3}$
$\sf use \: 3.14 \: for \: \pi : \\ = \frac{3.14 \times 10}{3}$
$\sf simplify \: multipication : \\ = \frac{31.4}{3} \\ \approx \: 10.47$

5 0

2 years ago

The average monthly rent for a? 1000-sq-ft apartment in a major metropolitan area from 1998 through 2005 can be approximated by

Lunna [17]

Answer:

t = 1.107

Step-by-step explanation:

Finding the solution using derivatives involves finding the lower zero of the quadratic that is the second derivative of the given function. That second derivative will be ...

f''(t) = 12(1.6714)t^2 -6(22.45)t +2(62.27)

= 20.0568t^2 -134.7t +124.54

= 20.0568(t -3.35796)² -101.619 . . . . rewrite to vertex form

Then f''(t) = 0 when ...

t ≈ 3.35796 -√(101.619/20.0568) ≈ 1.10706

The solution is perhaps more easily found using a graphing calculator to find the peak of the first derivative. (See attached.) It tells us ...

t ≈ 1.107

1.1 years after the beginning of 1998 is about 1.2 months into 1999.

Rents were increasing most rapidly in early February of 1999.