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3 years ago

Find DC (Image Below)

Mathematics

1 answer:

ioda3 years ago

6 0

Answer:

79239729379249

Step-by-step explanation:

your aswer is 284389300 oo

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Please answer quick it due today

Anarel [89]

Answer:

0.75 (75%) of a bag

Step-by-step explanation:

The question states that Frank has 3 bags and 4 bird feeders. In order to know how much of the bags he needs to add to each feeder, we are going to need to divide the amount of bags by the amount of feeders. This in term will give us an equal amount that should be added to each feeder. ... simplify We see from the calculation above that each feeder will get an equal amount of 0.75 (75%) of a bag.

Read more at Answer.Ya.Guru – https://answer.ya.guru/questions/741937-frank-has-3-bags-of-birdseed-he-wants-to-put-the-birdseed-into-4.html

4 0

2 years ago

Read 2 more answers

Compare 1/3 of 60 to 1/5 of 100

nataly862011 [7]

1/3 of 60 to 1/5 of 100 is 20 to 20.
1/3 x 60/1 =20
1/5 x 100/1=20
Reminder: You're able to cross-multiply.

6 0

3 years ago

Read 2 more answers

Veronica tells another classmate that ΔHAT is congruent to ΔPAM because of the AAA Theorem. Is Veronica correct in what she tell

SCORPION-xisa [38]

Answer: Veronica is not correct

Explanation:

The AAA theorem, aka the AA theorem, only applies to similar triangles. We cannot use it to prove two triangles are congruent or not. We would need to know info about at least one pair of sides. So based on this diagram, we don't have enough information to know if triangle HAT is congruent to triangle PAM or not.

A similar example to this is to consider two equilateral triangles. Let's call them triangle A and triangle B. If equilateral triangle A has side lengths of 2, and has side lengths of 10, we can see that the triangles are not congruent. However, the triangles are similar because the corresponding angles equal one another. One triangle is a scaled copy of the other. This example is a counterexample as to why the AAA theorem is not a valid congruence theorem.

3 0

2 years ago

Suppose you are managing 16 employees, and you need to form three teams to work on different projects. Assume that all employees

valentina_108 [34]

Answer:

4380 ways

Step-by-step explanation:

We have to form 3 project of 16 employees, they tell us that the first project must have 5 employees, therefore we must find the number of combinations to choose 5 of 16 (16C5)

We have nCr = n! / (R! * (N-r)!)

replacing we have:

1st project:

16C5 = 16! / (5! * (16-5)!) = 4368 combinations

Now in the second project we must choose 1 employee, but not 16 but 11 available, therefore it would be to find the number of combinations to choose 1 of 11 (11C1)

2nd project:

11C1 = 11! / (1! * (11-1)!) = 11 combinations

For the third project we must choose 10 employees, but since we only have 10 available, we can only do a combination of this, since 10C10 = 1, therefore:

3rd project: 1 combination

The total number of combinations fro selecting 16 employees for each project would be:

4368 + 11 + 1 = 4380 combinations, that is, there are 4380 different ways of forming projects with the given conditions.

3 0

3 years ago

Travis earned 92 bonus points. Zoe earned b more bonus points than Travis. Write an expression that shows how many bonus points

Serga [27]

92 + b= the amount of points Zoe earned

7 0

3 years ago

Read 2 more answers