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worty [1.4K]
3 years ago
8

Need help with this problem pics below!

Mathematics
1 answer:
Vikki [24]3 years ago
3 0

Answer:

37

Step-by-step explanation:

8 shape = 25

9 shape = 28

10 shape= 21

11 shape = 34

12 shape= 37

is adding by 3

<h2><u><em>hope it helps</em></u></h2><h2 />

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Simplify each of the following as a rational expression x+3/2x^2+9x+9 + 1/2(2x-3) - 4x/4x^2-9
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12.6% of<br>RI 149 390bn​
galina1969 [7]

Answer: RI 18,823.14

Step-by-step explanation:

I guess that we want to find the 12.6% of Rl 149,390

First, we assume that Rl 149,390 is the 100%

Then we can write an equation like:

Rl 149,390 = 100%

Then if the amount X is the 12.6%, we also have the equation:

X = 12.6%

Then we have the two equations:

X = 12.6%

Rl 149,390 = 100%

If we take the quotient between these two equations we get:

(X/Rl 149,390) = (12.6%/100%)

Solving this for X we get:

X =  (12.6%/100%)*(Rl 149,390) = RI 18,823.14

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Last spring, the drama department at Greenwood High School had 10 student audition for the musical. This spring, there were 8 st
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3 years ago
Write an equation of the perpendicular bisector of the segment with endpoints G 9,8       and H 3,2      .
Norma-Jean [14]

Answer:

y = -x + 11

Step-by-step explanation:

The equation of a straight line is is given by:

y = mx + b; where m is the slope and b is the y intercept

The equation of the line joining G(9, 8) and H(3, 2) is given as:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-8=\frac{2-8}{3-9}(x-9)\\\\y-8=x-9\\\\y=x-1

The perpendicular bisector of the line joining G(9, 8) and H(3, 2) is perpendicular to the line joining G(9, 8) and H(3, 2) and passes through the midpoint of line joining G(9, 8) and H(3, 2).

Let (x, y) be the midpoint of the line joining G(9, 8) and H(3, 2). Hence:

x = (9 + 3)/2 = 6

y = (8 + 2)/2 = 5

The midpoint = (6, 5)

Two lines are perpendicular if the product of their slopes is -1.

The line joining G(9, 8) and H(3, 2) has a slope of 1, hence, the slope of the perpendicular bisector would be -1.

This means that the perpendicular bisector has a slope of -1 and passes through (6, 5). Using:

y-y_1=m(x-x_1)\\\\y-5=-1(x-6)\\\\y-5=-x+6\\\\y=-x+11

The equation of the perpendicular bisector is y = -x + 11

8 0
3 years ago
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