Question

In ΔNOP, the measure of ∠P=90°, PO = 48, NP = 55, and ON = 73. What is the value of the sine of ∠N to the nearest hundredth?

Answer 1

Answer:

$\sin(N) = 0.66$

Step-by-step explanation:

Given

$\angle P = 90^o$

$PO = 48; NP = 55; ON = 73$

Required

$\sin(N)$

The given parameters is illustrated with the attached image.

From the attached, we have:

$\sin(N) = \frac{Opposite}{Hypotenuse}$

$\sin(N) = \frac{PO}{ON}$

$\sin(N) = \frac{48}{73}$

$\sin(N) = 0.66$ -- approximated