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Rom4ik [11]
3 years ago
12

Find the value of

id="TexFormula1" title="3 \frac{1}{5} \div \frac{8}{20} " alt="3 \frac{1}{5} \div \frac{8}{20} " align="absmiddle" class="latex-formula">


​
Mathematics
2 answers:
Nonamiya [84]3 years ago
4 0

Answer:

{ \bf{3 \frac{1}{5} \div \frac{8}{20} }} \\  =  \frac{16}{5}  \div  \frac{8}{20}  \\ { \boxed{ \tt{reciprocal \: of \:  \frac{8}{20}  =  \frac{20}{8} }}} \\  \therefore \:  =  \frac{16}{5}  \times  \frac{20}{8}  \\  =  \frac{320}{40}  \\  { \bf{ answer : 8}} \\  \\ {\underline{\tt {\blue{becker \: jnr}}}}

sesenic [268]3 years ago
4 0
3 1/5 must first converted into 16/5
Then, we can change the division into multiplication by changing 8/20 into it’s reciprocal, 20/8.
This gives us 16/5 * 20/8.
We can then simplify this to 2/1 * 4/1
You then multiply the two fractions to get 8/1 which is equivalent to 8.
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To test the impact performance of a 10 cm thick gymnastics mat, a 20 kg cylindrical
denis23 [38]

Answer:

A)196J

B)-208J

C)3467J

Step-by-step explanation:

We are given that a 20 kg cylindrical  mass is dropped onto the mat from a height of 1 m above the mat. During the impact,  the cylinder’s vertical velocity reaches zero at the instant the mat has compressed to  only 4 cm thick.

So, The Mat gets compressed by : 10cm - 4 cm = 6 cm=0.06 m

a)

Using Conservations of energy

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Kinetic energy = mgh= 20 \times 9.8 \times 1 = 196 J

b)

Work done  by the mat do to stop the fall of the cylinder =-mg(h+0.06)=-20 \times 9.8(1+0.06)=-208 J

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Work done=\text{Average force} \times \text{ Compression of mat}

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8 0
3 years ago
Please solve the math problem for me... I will mark you brainliest
natali 33 [55]

Answer:

x=34

Step-by-step explanation:

*it's kind of hard to read the number in parenthesis though but i think it's 5

both angles have to add up to 180º because they are co-exterior angles on parallel lines.

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6 0
2 years ago
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