Solve the equation and it will add up to -6 so
3×-7=-21
-21-10=-31
-31+25=-6
This expression is equivalent to:
[ 7^(log to the base 7 of 3)]^(-2), or [3]^(-2)], or 1/9.
Answer:
a) Right Tailed
b) p-value = 0.119
c) We fail to reject the Null Hypothesis(
)
Step-by-step explanation:
We have the following data:
Test Statistic = z = 1.18
Claim: p > 0.2
Part a) Type of Test
Remember that when there is Greater than, Lesser than or any synonymous word in the claim, this means that the test is one-tailed.
- Greater than word indicates a Right Tailed Test
- Lesser than word indicates a Left Tailed Test
Since, the claim is that p is greater than 0.2, the hypothesis test will be Right Tailed.
Part b) P-value
We have to find the p-value for the given test statistic. Since, the test statistic is a z-value we will use z-table to find the p-value for this score. Since, this z-score is for claim that p is greater than 0.2, so we will find the p-value(probability) of score being above 1.18
The p-value of z being greater than 1.18 comes out to be 0.119. i.e.
p-value = 0.119
Part c) Decision
Calculated p-value is 0.119 and significance level = 0.05. The rule is:
- If p value is equal to or lesser than the significance level, then we reject the null hypothesis
- If p value is greater than the significance level, then we fail to reject the null hypothesis
Since, in this case our p-value is greater than the significance level, we fail to reject the null hypothesis (
).
Answer:
graph (b)
Explanation:
The farm started with 40 sheep and the number doubled each year.
So, the equation modeling this situation would be:
N(x) = 40*(2)^2
By getting the equation, we can notice that we already excluded the third and fourth choices as they have the wrong equations.
Now, we will need to select the right graph which is either graph a or graph b.
To do this, we will get the value of N(x) for different values of x as follows:
At x = 0: N(0) = 40*(2)^0 = 40
At x = 1: N(1) = 40*(2)^1 = 80
At x = 1: N(2) = 40*(2)^2 = 160
Now, taking a look at graph a, we will find that:
N(1) = 120
N(2) = 360
These numbers are not the same as the numbers we calculated, therefore, this graph is wrong
Taking a look at graph b, we will find that:
N(1) = 80
N(2) = 160
These numbers are exactly the same as the ones calculated, therefore, this graph is the correct one.
Hope this helps :)
Answer:
x=1, y=2
Step-by-step explanation:
solve by substitution so substitute x= 6y-11 in the next equation
3 (6y-11) - 2y = -1
18y -33-2y = -1
16y = 33-1
y= 32/16 =2
x= 6y -11 = 6*2 -11 = 12 -11 = 1