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Free_Kalibri [48]
3 years ago
7

Unit 8 7th grade math

Mathematics
1 answer:
sergejj [24]3 years ago
8 0
The mean is 9
First you add all the number then you divide by the amount of numbers
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Help please !!:) For y =3x -2x^2 +5x^3 show how to find the value for y when x = 3
victus00 [196]

y = 3x-2x∧2+5x∧3

When we replace x with value 3 we get

y = 3 * 3 - 2 * 3∧2 + 5 * 3∧3 => y = 9-2*9+5*27 => y = 9-18+135 => y = 126

good luck!!!

7 0
4 years ago
What is 10 times 7 thousands
velikii [3]
70,000 is the answer
7 0
4 years ago
A parabolic arch has a height of 25 feet and a span of 40 feet. How high is the arch 8 feet from each side of the center?
Llana [10]

Answer:

The correct option is;

21 ft

Step-by-step explanation:

The equation of the parabolic arc is as follows;

y = a(x - h)² + k

Where the height is 25 ft and the span is 40 ft, the coordinates of the vertex (h, k) is then (20, 25)

We therefore have;

y = a(x - 20)² + 25

Whereby the parabola starts from the origin (0, 0), we have;

0 = a(0 - 20)² + 25

0 = 20²a + 25 → 0 = 400·a + 25

∴a = -25/400 = -1/16

The equation of the parabola is therefore;

y = (-\frac{1}{16})(x-20)^2 + 25

To find the height 8 ft from the center, where the center is at x = 20 we have 8 ft from center = x = 20 - 8 = 12 or x = 20 + 8 = 28

Therefore, plugging the value of x = 12 or 28 in the equation for the parabola gives;

y = (-\frac{1}{16})(12-20)^2 + 25 = (-\frac{1}{16})(-8)^2 + 25 = 21 \ ft.

4 0
3 years ago
Ready ready upp here we goooooooooo
garik1379 [7]

Answer:

all of them

Step-by-step explanation:

:)

yepppp I'm pretty surr

8 0
3 years ago
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Suppose a figure is located in Quadrant I. Which of the following sequences will result in an image that is located in Quadrant
vladimir2022 [97]
The answer that results in an image located in Quadrant II is <span>C. rotate 90 degrees counterclockwise, then shift 1 unit up. This is because Quadrant II is located next (at the left) of Quadrant I. This means that a 90 degree rotation and a shift up are safe enough to estimate it to land on Quadrant II.</span>
4 0
3 years ago
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