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3 years ago

The domain of f(x)= (2/3)^x is all negative numbers true or false

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

4 0

False, probably. cause (2/3)^1 is defined

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NEED ANSWER ASAP!!! WILL GIVE BRAINLIEST TO WHO ANSWERS FIRST!

alexandr1967 [171]

Answer:

x < - 4

Step-by-step explanation:

Given

2x - 2 > 4x + 6 ( subtract 2x from both sides )

- 2 > 2x + 6 ( subtract 6 from both sides )

- 8 > 2x ( divide both sides by 2 )

- 4 > x , thus

x < - 4

8 0

3 years ago

I WILL GIVE BRAINLIEST

shusha [124]

Answer:

x = -3

Step-by-step explanation:

$y\geq -\frac{2}{3} x-3\\
y\leq 3x+8$

$-\frac{2}{3} x-3=3x+8$

Add 2/3 x to both sides: $-3=\frac{11}{3}x+8$

Subtract 8 from both sides: $-11=\frac{11}{3}x$

Multiply both sides by 3: $-33=11x$

Divide both sides by 11: $x=-3$

Therefore, point of intersection between both lines is at point (-3, -1)

5 0

2 years ago

Determine which property is demonstrated below;

aniked [119]

Answer:

symmetric property

Step-by-step explanation:

The <em>symmetric property</em> is the one that tells you A=B means also B=A.

The obfuscating factor in this question is the renaming of angle SZW to angle WZS. Both names refer to the same angle.

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3 years ago

3n *power 2 +10n+7 how to factories and pls tell with solution

tankabanditka [31]

Answer:

(n + 1)(3n + 7)

Step-by-step explanation:

3n² + 10n + 7

Consider the factors of the product of the n² term and the constant term which sum to give the coefficient of the n- term.

product = 3 × 7 = 21 and sum = + 10

The factors are + 3 and + 7

Use these factors to split the n- term

3n² + 3n + 7n + 7 ( factor the first/second and third/fourth terms )

3n(n + 1) + 7(n + 1) ← factor out (n + 1) from each term

= (n + 1)(3n + 7) ← in factored form

5 0

3 years ago

Read 2 more answers

Find the difference. express your answer in simplest form. (2s/s^2-4s+4) - (4/s^2-4s+4)

LUCKY_DIMON [66]

To find the difference, we are going to destroy the parenthesis first, and then, we are going to perform the operations. Remember that to destroy a parenthesis preceded by a negative sign (-), you should change the signs of the factors inside the parenthesis:
$\frac{2s}{s^2-4s+4} -( \frac{4}{s^2-4s+4} )$
$\frac{2s}{s^2-4s+4} -\frac{4}{s^2-4s+4}= \frac{2s-4}{s^2-4s+4}$

Now we can factor both numerator and denominator and simplify:
$\frac{2s-4}{s^2-4s+4} = \frac{2(s-2)}{(s-2)^2} = \frac{2}{s-2}$

We can conclude that the difference in simplest form is: $\frac{2}{s-2}$

5 0

4 years ago

Read 2 more answers