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Delicious77 [7]
2 years ago
7

Which expression is equivalent to 1/3 divided by 1/6

Mathematics
1 answer:
leonid [27]2 years ago
5 0

Answer:

The answer is A

Step-by-step explanation:

cross mutliply

1×6=6

1×3=3

divide the answers

result: 2

I hope this helps

You might be interested in
Which expression is equivalent to (3x2+3x−3)−(6x2−4x−2)?
coldgirl [10]

Answer:

A. -3x^2+7x-1

Step-by-step explanation:

(3x^2+3x-3)-(6x^2-4x-2)

3x^2+3x-3-6x^2+4x+2

-3x^2+7x-1

4 0
3 years ago
Kristin wants to wrap a ribbon around the perimeter of a rectangle. The length is five less than twice the width. The perimeter
romanna [79]

The length of the rectangle is 51 inches while the width of the rectangle is 28 inches.

Since Kristin wants to wrap a ribbon around the perimeter of a rectangle, the perimeter of a rectangle P = 2(L + W) where L = length of rectangle and W = width of rectangle.

Given that the perimeter of the rectangle, P = 56 inches and the length of the rectangle, L is five less than twice the width of the rectangle, W we have that

L = 2W - 5

Substituting L into P, we have

P = 2(2W - 5 + W)

P = 2(W - 5)

Since P = 56, we have

2(W - 5) = 56

~Dividing both sides by 2, we have

W - 5 = 56/2

W - 5 = 23

Adding 5 to both sides, we have

W = 23 + 5

W = 28 inches

Substituting W into L, we have

L = 2W - 5

L = 2(28) - 5

L = 56 - 5

L = 51 inches

So, the length of the rectangle is 51 inches while the width of the rectangle is 28 inches.

Learn more about perimeter of a rectangle here:

brainly.com/question/16715918

5 0
3 years ago
Delta math helpppp!!!!!!!!!
jasenka [17]
Neither parallel nor perpendicular


Hope this helps! :D
7 0
3 years ago
Suppose that 35 people are divided in a random mannerinto two teams in such a way that one team contains10 people and the other
Alisiya [41]

To be precise, the size of your sample space is <span><span>(<span>2410</span>)</span><span>(<span>2410</span>)</span></span>. This number does go on the bottom of the fraction, and what goes on top is the size of the event. Break up the event into independent events 1. choose the 2 defective bulbs, and 2. choose the remaining 8 bulbs. I don't have much choice in event 1. There is only one way to choose both of the defective balls. In other words, <span><span>(<span>22</span>)</span><span>(<span>22</span>)</span></span> (choosing 2 defective bulbs from a set of 2 defective bulbs). For event 2, there are <span><span>24−2=22</span><span>24−2=22</span></span> nondefective bulbs, and I must choose <span>88</span> of them, so that's <span><span>(<span>228</span>)</span><span>(<span>228</span>)</span></span>. Finally, since events 1 and 2 are independent, we multiply the answers for the combined event: <span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span></span>

<span><span>P=<span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span><span>(<span>2410</span>)</span></span></span><span>P=<span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span><span>(<span>2410</span>)</span></span></span></span>

Or, since <span><span><span>(<span>22</span>)</span>=1</span><span><span>(<span>22</span>)</span>=1</span></span>,

<span><span>P=<span><span>(<span>228</span>)</span><span>(<span>2410</span>)</span></span></span><span>P=<span><span>(<span>228</span>)</span><span>(<span>2410</span>)</span></span></span></span>

Hope this helps!

7 0
3 years ago
I need help with number 2 please.
Vedmedyk [2.9K]
The answer is 73.33333333 (repeated). You can also write it as 73 or 73.3 with a line over the 3 (after the decimal point) to indicate it being repeated.
8 0
3 years ago
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