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Katyanochek1 [597]
2 years ago
6

it takes engineer 3 hrs to drive to his brother's house at an average of 50 miles per hour. if he takes same route home, but his

average speed of 60 miles per hour, what is the time, in hours, that it takes him to drive home?​
Mathematics
2 answers:
Katarina [22]2 years ago
7 0

Answer:

t2 = 2.5 hours.

Step-by-step explanation:

The distance is the same.

d = r * t

The rates and times are different so

t1 = 3 hours

t2 = X

r1 = 50 mph

r2 = 60 mph

r1 * t1 = r2*t2

50 * 3 = 60 * t2

150 = 60 * t2

150 / 60 = t2

t2 = 2.5

jasenka [17]2 years ago
3 0

Answer:

Answer: Travel Time is 2 hours & 30 minutes

Step-by-step explanation:

Original Journey Time is 3 hours, Speed is 50 mph, Distance is 150 miles

Original Distance is 150 miles, New Speed is 60 mph.

Also Combined Distance was 300 miles, Combined Time was 5 hours & 30 minutes. therefore: Average Speed for complete round trip is 54. 54 mph

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Solve using substitution. <br> 7x-4y=-12<br> 9x-4y=-20
MrRissso [65]

Answer:y= -4

Step-by-step explanation:

1 Solve for xx in 7x-4y=-127x−4y=−12.

x=\frac{4(y-3)}{7}

x=

7

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​

2 Substitute x=\frac{4(y-3)}{7}x=

7

4(y−3)

​

 into 9x-4y=-209x−4y=−20.

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36(y−3)

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−4y=−20

3 Solve for yy in \frac{36(y-3)}{7}-4y=-20

7

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​

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.

x=-4

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​

 

x=−4

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​

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