Given :
A function , x = 2cos t -3sin t .....equation 1.
A differential equation , x'' + x = 0 .....equation 2.
To Find :
Whether the given function is a solution to the given differential equation.
Solution :
First derivative of x :

Now , second derivative :

( Note : derivative of sin t is cos t and cos t is -sin t )
Putting value of x'' and x in equation 2 , we get :
=(-2cos t + 3sin t ) + ( 2cos t -3sin t )
= 0
So , x'' and x satisfy equation 2.
Therefore , x function is a solution of given differential equation .
Hence , this is the required solution .
Answer:
I believe they ate 4/8. 2 apple and 2 banana muffins makes 4. They still have 4 blueberry muffins left. so 4/8
Answer:
x = 2
Step-by-step explanation:
3(5x - 2) + 1 = 25 (Given)
3(5x) + 3(-2) + 1 = 25 (Distributive Property of Equality)
15x + -6 + 1 = 25 (Simplify)
15x - 5 = 25 (Simplify)
15x + 5 + 5 = 25 + 5 (Addition Property of Equality)
15x = 30 (Simplify)
(Division Property of Equality)
x = 2 (Simplify)
Answer:
option B
Step-by-step explanation:





15x^2-15x+21x-21
15x^2+6x-21 is the answer