Let i = sqrt(-1) which is the conventional notation to set up an imaginary number
The idea is to break up the radicand, aka stuff under the square root, to simplify
sqrt(-8) = sqrt(-1*4*2)
sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)
sqrt(-8) = i*2*sqrt(2)
sqrt(-8) = 2i*sqrt(2)
<h3>Answer is choice A</h3>
Answer:
<h2>
4, 7, 10, 13 and 16</h2>
Step-by-step explanation:
The nth term of an arithmetic sequence is expressed as
.
a is the first term of the sequence
d is the common difference
n is the number of terms
Given the first term a = 4 and common difference d = 3, we can calculate the first five terms of the sequence using the formula.
If n = 2

The first five terms of the sequence from lowest to highest are 4, 7, 10, 13 and 16
It is (d)
She has a decrease of $1.25 so d-1.25