All categories

3 years ago

How do I do this problem with solution by elimination? 2x+y=3 -2x+5y=-9

Mathematics

1 answer:

ddd [48]3 years ago

7 0

Answer:

(2, -1)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Algebra I

Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

2x + y = 3

-2x + 5y = -9

Step 2: Solve for y

Elimination

Combine equations: 6y = -6
Divide 6 on both sides: y = -1

Step 3: Solve for x

Define equation: 2x + y = 3
Substitute in y: 2x - 1 = 3
Isolate y term: 2x = 4
Isolate y: x = 2

You might be interested in

What is the area of the triangle that is 30 m base in the height of 12 m in a straight line of 13

Reika [66]

Answer:

Step-by-step explanation:

3 0

3 years ago

10. A local

professor190 [17]

Answer:

39.7%

Step-by-step explanation:

(actual value - estimated value) / actual value

5.8 - 3.5 = 2.3

2.3 / 5.8 = 0.3965 = 39.65%

5 0

3 years ago

In a dog show, there will be a gold and a silver medal awarded. There are

Svetradugi [14.3K]

10 different ways the awards can be rewarded.

5 0

3 years ago

(16+5i) + (6-7i) How do I solve this?

Fantom [35]

Answer:

$\large\boxed{(16+5i)+(6-7i)=22-2i}$

Step-by-step explanation:

$(16+5i)+(6-7i)=16+5i+6+7i\qquad\text{combine like terms}\\\\=(16+6)+(5i-7i)=22-2i$

5 0

3 years ago

Read 2 more answers

In a sociology class there are 1414 sociology majors and 1111 non-sociology majors. 33 students are randomly selected to present

saul85 [17]

Answer: $0.4065$

Step-by-step explanation:

Given : In a sociology class there are 14 sociology majors and 11 non-sociology majors.

Total students = 14+11=25

Number of students are randomly selected = 3

Then, the number of ways to select 3 students from 25 students :-

$^{25}C_3=\dfrac{25!}{(25-3)!3!}=\dfrac{25\times24\times23\times22!}{22!3!}\\\\=2300$

Number of ways to select at least 2 of the 3 students re non-sociology majors :-

$^{14}C_1\times^{11}C_2+^{14}C_0\times ^{11}C_{3}\\\\=(14)\times\dfrac{11!}{2!(11-2)!}+(1)\times\dfrac{11!}{3!(11-3)!}\\\\=(14)(11\times5)+\dfrac{11\times10\times9}{6}\\\\=770+165=935$

The probability that at least 2 of the 3 students selected are non-sociology majors will be :-

$\dfrac{935}{2300}=0.40652173913\approx0.4065$

8 0

3 years ago