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3 years ago

How do I do this problem with solution by elimination? 2x+y=3 -2x+5y=-9

Mathematics

1 answer:

ddd [48]3 years ago

7 0

Answer:

(2, -1)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Algebra I

Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

2x + y = 3

-2x + 5y = -9

Step 2: Solve for y

Elimination

Combine equations: 6y = -6
Divide 6 on both sides: y = -1

Step 3: Solve for x

Define equation: 2x + y = 3
Substitute in y: 2x - 1 = 3
Isolate y term: 2x = 4
Isolate y: x = 2

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HELP FOR POINTSS

brilliants [131]

The answer would be
C = 10
P = 20

3 0

3 years ago

Read 2 more answers

1-2n) - 7n(12-2) simplify this and show work

Natasha2012 [34]

For this case we must simplify the following expression:

$(1-2n) -7n (12-2) =$

We solve the operation of the second parenthesis, taking into account that different signs are subtracted and the sign of the major is placed:

$(1-2n) -7n (10) =$

We multiply:

$(1-2n) -70n =$

We eliminate the parentheses:

$1-2n-70n =$

We add similar terms, taking into account that equal signs are added and the same sign is placed:

$1-72n$

Answer:

The simplified expression is: $1-72n$

5 0

3 years ago

Translating verbal sentences: 16 decreased by a number is 27

Julli [10]

16 - x = 27
x = -11

16 - x = 27

16 = 27 + x

16 - 27 = x

-11 = x

4 0

3 years ago

5⁸ – = 5ⁿ 5⁴ work out the value of n.

Hitman42 [59]

Answer:

5 power 2 is the answer

Step-by-step explanation:

7 0

3 years ago

Please help me and we should use laws of exponents

elena55 [62]

Answer:

3.b

$(\frac{8}{3})^{2x+1} *(\frac{8}{3})^{5} =(\frac{8}{3}) ^{x+2}\\\\(\frac{8}{3})^{2x+1 +5} =(\frac{8}{3}) ^{x+2}\\\\\\2x +6 = x+2\\x = -4$

i hope question 3.a. is 5^x ÷ 5^-3 = 5^5

3.a.

$\frac{5^x}{5^{-3}} = 5^5\\\\5^ {x+3} = 5^5\\\\x+3 = 5\\x =2$

6 0

3 years ago