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lys-0071 [83]
3 years ago
15

Please help! (I'll give brainliest to the first right answer)

Mathematics
1 answer:
eduard3 years ago
5 0

Answer:

1/2: the fourth quadrant

3/4:"Q1: 4,5" "Q2: 4,-1" "Q3: -2,-3" "Q4: 5, -2"

Step-by-step explanation:

hope this helps!

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Please help i will mark as brainlest please help me
uysha [10]

Answer:

  • A.

Step-by-step explanation:

<u>Here is how I found it:</u>

  • Flip the picture 180°.
  • Then, measure the angle.

<em>Required:</em>

  • The angle is 90°.
  • If you don't pay attention, you might mistake it for a 150° angle.

Correct choice is A.

5 0
2 years ago
The points (-4,r) and (2,-3) lie on a line with a slope-1. Find the missing coordinator r.?
MAVERICK [17]

Answer:

3 (-4,3)

Step-by-step explanation:

7 0
3 years ago
Two lighthouses are located 75 miles from one another on a north-south line. If a boat is spotted S 40o E from the northern ligh
yuradex [85]

Answer:

The northern lighthouse is approximately 24.4\; \rm mi closer to the boat than the southern lighthouse.

Step-by-step explanation:

Refer to the diagram attached. Denote the northern lighthouse as \rm N, the southern lighthouse as \rm S, and the boat as \rm B. These three points would form a triangle.

It is given that two of the angles of this triangle measure 40^{\circ} (northern lighthouse, \angle {\rm N}) and 21^{\circ} (southern lighthouse \angle {\rm S}), respectively. The three angles of any triangle add up to 180^{\circ}. Therefore, the third angle of this triangle would measure 180^{\circ} - (40^{\circ} + 21^{\circ}) = 119^{\circ} (boat \angle {\rm B}.)

It is also given that the length between the two lighthouses (length of \rm NS) is 75\; \rm mi.

By the law of sine, the length of a side in a given triangle would be proportional to the angle opposite to that side. For example, in the triangle in this question, \angle {\rm B} is opposite to side \rm NS, whereas \angle {\rm S} is opposite to side {\rm NB}. Therefore:

\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of NB}}{\sin(\angle {\rm S})} \end{aligned}.

Substitute in the known measurements:

\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of NB}}{\sin(21^{\circ})} \end{aligned}.

Rearrange and solve for the length of \rm NB:

\begin{aligned} & \text{length of NB} \\ =\; & (75\; \rm mi) \times \frac{\sin(21^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 30.73\; \rm mi\end{aligned}.

(Round to at least one more decimal places than the values in the choices.)

Likewise, with \angle {\rm N} is opposite to side {\rm SB}, the following would also hold:

\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of SB}}{\sin(\angle {\rm N})} \end{aligned}.

\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of SB}}{\sin(40^{\circ})} \end{aligned}.

\begin{aligned} & \text{length of SB} \\ =\; & (75\; \rm mi) \times \frac{\sin(40^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 55.12\; \rm mi\end{aligned}.

In other words, the distance between the northern lighthouse and the boat is approximately 30.73\; \rm mi, whereas the distance between the southern lighthouse and the boat is approximately 55.12\; \rm mi. Hence the conclusion.

4 0
2 years ago
What is the rule input numbers are 17 18 _ 28_40
Lelu [443]
19 27 28 29 30 315 64 29 46 is the 
\
4 0
3 years ago
120 times 1.75 show your work plz help me I really dont get it
sineoko [7]
120 * 1.75 = 200

5 times 0 = 0

5 times 2 = 10 carry the 1

5 times 1 = 5 + 1 = 6

7 times 0 = 0

7 times 2 = 14 carry the 1...

7 times 1 = 7 + 1 = 8
1 times 0 = 0
1 times 2 = 2
1 times 1 = 1
add it all together and you get 200.
6 0
3 years ago
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