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lys-0071 [83]
3 years ago
15

Please help! (I'll give brainliest to the first right answer)

Mathematics
1 answer:
eduard3 years ago
5 0

Answer:

1/2: the fourth quadrant

3/4:"Q1: 4,5" "Q2: 4,-1" "Q3: -2,-3" "Q4: 5, -2"

Step-by-step explanation:

hope this helps!

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how do you solve y=x+4 and y=-2x+1 using the subsituation method and show work and please give me the correct answer
SIZIF [17.4K]

Answer:

(-1,3)

Step-by-step explanation:

so y=x+4 and y=-2x+1

obviously, y=y

so that means that x+4 is equal to -2x+1

let's use that

y=x+4,y=-2x+1

y=y

x+4=-2x+1

x+2x=1-4

3x=-3

x=-1

y=x+4

y=(-1)+4

y=3

(-1,3)

6 0
3 years ago
Suppose a teacher gives 10 points for putting your name on a 100 point test. The minimum score on that test is 10 and the maximu
Varvara68 [4.7K]
I think it is x+10=>100
8 0
3 years ago
If(x) = x + 2 and h(x) = x-1, what is f • h](-3)?
deff fn [24]

Answer/Step-by-step explanation:

Composition functions are functions that combine to make a new function. We use the notation ◦ to denote a composition.

f ◦ g is the composition function that has f composed with g. Be aware though, f ◦ g is not

the same as g ◦ f. (This means that composition is not commutative).

f ◦ g ◦ h is the composition that composes f with g with h.

Since when we combine functions in composition to make a new function, sometimes we

define a function to be the composition of two smaller function. For instance,

h = f ◦ g (1)

h is the function that is made from f composed with g.

For regular functions such as, say:

f(x) = 3x

2 + 2x + 1 (2)

What do we end up doing with this function? All we do is plug in various values of x into

the function because that’s what the function accepts as inputs. So we would have different

outputs for each input:

f(−2) = 3(−2)2 + 2(−2) + 1 = 12 − 4 + 1 = 9 (3)

f(0) = 3(0)2 + 2(0) + 1 = 1 (4)

f(2) = 3(2)2 + 2(2) + 1 = 12 + 4 + 1 = 17 (5)

When composing functions we do the same thing but instead of plugging in numbers we are

plugging in whole functions. For example let’s look at the following problems below:

Examples

• Find (f ◦ g)(x) for f and g below.

f(x) = 3x + 4 (6)

g(x) = x

2 +

1

x

(7)

When composing functions we always read from right to left. So, first, we will plug x

into g (which is already done) and then g into f. What this means, is that wherever we

see an x in f we will plug in g. That is, g acts as our new variable and we have f(g(x)).

g(x) = x

2 +

1

x

(8)

f(x) = 3x + 4 (9)

f( ) = 3( ) + 4 (10)

f(g(x)) = 3(g(x)) + 4 (11)

f(x

2 +

1

x

) = 3(x

2 +

1

x

) + 4 (12)

f(x

2 +

1

x

) = 3x

2 +

3

x

+ 4 (13)

Thus, (f ◦ g)(x) = f(g(x)) = 3x

2 +

3

x + 4.

Let’s try one more composition but this time with 3 functions. It’ll be exactly the same but

with one extra step.

• Find (f ◦ g ◦ h)(x) given f, g, and h below.

f(x) = 2x (14)

g(x) = x

2 + 2x (15)

h(x) = 2x (16)

(17)

We wish to find f(g(h(x))). We will first find g(h(x)).

h(x) = 2x (18)

g( ) = ( )2 + 2( ) (19)

g(h(x)) = (h(x))2 + 2(h(x)) (20)

g(2x) = (2x)

2 + 2(2x) (21)

g(2x) = 4x

2 + 4x (22)

Thus g(h(x)) = 4x

2 + 4x. We now wish to find f(g(h(x))).

g(h(x)) = 4x

2 + 4x (23)

f( ) = 2( ) (24)

f(g(h(x))) = 2(g(h(x))) (25)

f(4x

2 + 4x) = 2(4x

2 + 4x) (26)

f(4x

2 + 4x) = 8x

2 + 8x (27)

(28)

Thus (f ◦ g ◦ h)(x) = f(g(h(x))) = 8x

2 + 8x.

4 0
3 years ago
If y = -6cosx, what is the amplitude?
aniked [119]

 

\displaystyle\bf\\y=-6cos\,x\\\\\textbf{is equivalent to:}\\\\y=6cos(x+\pi)\\\\\textbf{where 6 is the maximum value or amplitude}\\\\\implies~~~\boxed{\bf~amplitude=6}

 

8 0
3 years ago
A bag contains orange and yellow sweets the ratio of orange to yellow sweets is 3:2 There are 51 orange sweets in the bag find t
GalinKa [24]

Answer: 34

Step-by-step explanation: the ratio is 3:2 we know that there are 51 orange sweets but we don’t know how many are yellow so the current ratio is 51:x we need to find x so if we divide 3 by 51 the answer is 17 so we need to multiply 17 by 2 which is 34 so x is equaled to 34 the final ratio is 51:34

hope it helped :)

6 0
3 years ago
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