Step-by-step answer:
Please refer to attached image.
1. Quad PQRS is cyclic (all vertices on the same circle), so opposite angles are supplementary, meaning
that
angles QPS and QRS are supplementary =>
QPS+QRS=180 =>
QRS = 180 - 74 = 106
2. Triangle RSQ is isosceles with RS=RQ =>
angles RSQ and RQS are congruent.
3. Angle RSQ = (180 - 106) /2 = 74 / 2 = 37
4. QP is a diameter => angle QSP is a right-angle.
5. From (3) and (4) above,
angle RSP = 37+90 = 127
6. Since PQRS is cyclic, angles RQP and RSP are supplementary =>
RQP+RSP = 180 =>
x + 127 = 180 =>
x = 180 - 127 = 53 degrees.
The sum of the sequence is 750
<h3>How to determine the sum of the series?</h3>
The series is given as:
150, 120, 96, and 76.8,
Start by calculating the common ratio using:
r = T2/T1
This gives
r = 120/150
r = 0.8
The sum of the series is then calculated as:

This gives

Evaluate
S = 750
Hence, the sum of the sequence is 750
Read more about sequence at:
brainly.com/question/6561461
#SPJ1
Answer:
Step-by-step explanation:
It asks for the common set of A and B.
<u>There only one element common to both the given sets:</u>
- A={2,3,5,7} and B={2,4,6,8} ⇒ A∩B = {2}
The equation you had:
6x + 5y = 45
Solve for Y:
5y = (-6x) + 45 divide by 5
y = (-6/5)x + 9
y = -1 1/5x +9