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Greeley [361]
3 years ago
9

Which is the algebraic sentence for "a number decreased by 6 is 12"?

Mathematics
2 answers:
solniwko [45]3 years ago
8 0

Answer:

x - 6 = 12 is the answer

im 100% sure

yan [13]3 years ago
6 0

Answer:

x-6=12

Step-by-step explanation:

X=12+6

X=18

substitute for X in the equation

18-6=12

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Explaination: it goes through the 6 and -3 points in the slope.
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Make a conjecture. What properties do you think stay the same after a translation? Check all that Apply.
Ilia_Sergeevich [38]

Answer: ALL OF THE ABOVE

Step-by-step explanation:

a translation doesn't change any of the above, they all remain the same. it's a trick question :P

8 0
3 years ago
Can anyone help solve this for me ASAP. Thanks!
Anuta_ua [19.1K]

Answer:

x = 20

y = 26

Step-by-step explanation:

40 and 2x are vertical angles, so they're equal to each other.

40 = 2x

Divide both sides by 2

x = 20

We see that 40 and 5y + 10 are a linear pair, which means they add up to 180.

5y + 10 + 40 = 180

5y + 50 = 180

5y = 130

y = 26

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3 years ago
What does this mean?<br> "9!"<br> I did not learn this yet.
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6 0
3 years ago
Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun
WITCHER [35]

Answer:

Required solution (a) f(x,y,z)=xyz+3z^2+C (b) 40.

Step-by-step explanation:

Given,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k

(a) Let,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}

Then,

f_x=yz,f_y=xz,f_z=xy+6z

Integrating f_x we get,

f(x,y,z)=xyz+g(y,z)

Differentiate this with respect to y we get,

f_y=xz+g'(y,z)

compairinfg with f_y=xz of the given function we get,

g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)

Then,

f(x,y,z)=xyz+h(z)

Again differentiate with respect to z we get,

f_z=xy+h'(z)=xy+6z

on compairing we get,

h'(z)=6z\implies h(z)=3z^2+C   (By integrating h'(z))  where C is integration constant. Hence,

f(x,y,z)=xyz+3z^2+C

(b) Next, to find the itegration,

\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40

3 0
3 years ago
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