The solution for proving the identity is as follows:
sin(2A) = sin(A + A)
As sin(a + b) = sinacosb + sinbcosa,
<span>sin(A + A) = sinAcosA + sinAcosA
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<span>Therefore, sin(2A) = 2sinAcosA
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Answer:
Zero real roots:
f(x) = x^2-x+1
f(x) = x^2+2x+3
One real root:
Two real roots:
f(x)=x^2+2x+1
f(x)=x^2-3x+2
Step-by-step explanation:
These were determined by using the quadratic formula.
The equations are dependent (they're the same equation).
If you multiply the bottom one by 5, you get the top one.
Answer:
square root 48
Step-by-step explanation:
It is square root 48 because it is between 7 and 8 not exactly if it was exactly 7 and 8 it would be square root 56
Answer:
1/2k-3/5
Step-by-step explanation:
