<h3>(1136+1272)-(1138+{-1250})</h3><h3>=2408-(-112)</h3><h3>=2408+112</h3><h3>=2520</h3><h3>the answer is 2520</h3><h2 /><h2 /><h2>hope it helped :-)</h2>
Answer:
Area of rectangle: 256
Area of triangle 1: 24
Area of triangle 2: 16
Area of triangle 3: 96
Area of trapezoid: 120
Step-by-step explanation:
I just did the question on the thing so Ik I'm right.
-The graph measures by twos. To get the area of the rectangle get the base times height of it. That would be 16x16=256.
-Get base (8) times height (6) of triangle 1 then divide by 2, remember to count the squares by 2 for finding all areas. The formula would be 1/2(b)(h) because dividing by 2 is the same as multiplying times 1/2. Plug it in and (8)(6)=48 then divide by 2 which equals 24.
-Same formula for triangle 2. Plug it in and (8)(4)=32 and divide by 2 and it equals 16.
-Same formula for triangle 3. Plugged in is (12)(16)=192 divide by 2 and it equals 96.
-To find the area of the trapezoid get your rectangle area (256) and subtract all the triangle areas. So 256 - 6 - 16 - 96 = 120.
Answer:
3
Step-by-step explanation:
Given
15 gold ribbons
22 blue ribbons
53 red ribbons
Total of 53 + 22 + 15 = 90 ribbons
Total number of students = 12 boys + 18 girls = 30 students.
If evenly divided, each student will have 90/30 = 3 ribbons
The expression to solve would basically be the amalgamation of what we did above:
(53 + 22 + 15)/(12+18)
1017, maybe, i hope its right, sorry if its not:)
The number in the parenthesis is the X value and they are looking for what the Y value is at that specific X.
So when you look at f(-2), find the Y value where the line crosses.
At X-2, the line crosses Y at -2
At X = 2, the line crosses at Y = 2
At X = 4, the line crosses at Y = 1
The answer is -2,2,1
