Write a system of equation based on the number
For an instance, the two numbers are a and b.
"The sum of two numbers is 59" can be written as follows.
⇒ a + b = 59 <em>(first equation)
</em>"The difference is 15" can be written as follows.
⇒ a - b = 15 <em>(second equation)</em>
Solve the system of equation by elimination/substitution method.
First, eliminate b to find the value of a.
a + b = 59
a - b = 15
--------------- + (add)
2a = 74
a = 74/2
a = 37
Second, substitute 37 as a in one of the equations
a + b = 59
37 + b = 59
b = 59 - 37
b = 22
The numbers are 37 and 22
Answer:
bigger
Step-by-step explanation:
-3 is bigger then -12
Ax + By = C form of the given equation is –6x + y = –28.
Solution:
Given equation is y – 2 = 6(x – 5).
To write the equation in Ax + By = C format:
y – 2 = 6(x – 5)
y – 2 = 6x – 30
Add 2 on both sides of the equation.
y – 2 + 2 = 6x – 30 + 2
y = 6x – 28
Subtract 6x from both sides of the equation.
y – 6x = 6x – 28 – 6x
y – 6x = –28
Arrange the terms in the equation.
–6x + y = –28
This is in the form of Ax + By = C.
Here A = –6, B = 1 and C = –28.
Let p = number of pennies.
Let n = number of nickels.
We are given that n= 2p and the total value is $8.80.
We know that a penny = $0.01 and that a nickel = $0.05.
So $0.01p + $0.05n = $8.80.
Substitute 2p for n:
$0.01p + $0.05*2p = $8.80
$0.01p + $0.10p = $8.80
$0.11p = $8.80
p = 80
So n = 2p = 2*80 = 160
Thus there are 80 pennies ($0.8) and 160 nickels ($8.00). The value of all the coins is $8.80.
