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lawyer [7]
3 years ago
10

The legs of a right triangle are 10 and 12. What is the length of the hypotenuse in simplest radical form?

Mathematics
2 answers:
guajiro [1.7K]3 years ago
6 0
The correct answer it’s A
Firlakuza [10]3 years ago
4 0

Answer:

2 * sqrt(61)

Step-by-step explanation:

a = 10

b = 12

c = ?

c^2 = a^2 + b^2

c^2 = 10^2 + 12^2

c^2 = 100 + 144

c^2 = 244

c^2 = 4 * 61

sqrt(c^2) = sqrt(4) * sqrt(61)

c = 2 * sqrt(61)

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The sum of three consecutive even integers is 264. What are the integers? (show your work)
Anettt [7]

Answer:

1 Expert Answer

X + Y + Z = 264. Since Y is 1 bigger than X, Y = X + 1. Since Z is 1 bigger than Y, Z = Y + 1. But Y = X + 1, so Z = (X + 1) + 1 = X + 2.

4 0
2 years ago
At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?
hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

d*sin(\theta) = m\lambda

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle              

At the first-order maximum (m=1) at 20.0 degrees we have:

\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342

Now, to produce a second-order maximum (m=2) the angle must be:

sin(\theta) = \frac{\lambda}{d}*m

\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.    

I hope it helps you!                                                        

6 0
3 years ago
What is the following product
Sloan [31]

Answer:

option D

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4 0
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