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kompoz [17]
2 years ago
6

A home goods store purchased a desk lamp and marked it up 155% from the original cost of $9.12. Then, wanting to make room for s

ummer inventory, the store placed the desk lamp on sale for 30% off. What was the price after the discount?
Mathematics
1 answer:
erma4kov [3.2K]2 years ago
6 0

Answer:

16.28

Step-by-step explanation:

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Evaluate the expression.
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Answer:

add my sc = bmic ava, no spaces

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Step-by-step explanation:

Also have a great day and remember youre worth, dont let no boy/girl tear u down. leave them h*es aside and focus on yo self!!!

4 0
3 years ago
The table shows how Mura spends her free time on a typical Saturday.if she has 6hours of free time how many hours does she spend
ycow [4]

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1 year ago
Divide 21 by g. Then, subtract 6.
IrinaVladis [17]
21/g - 6 = (21-6g)/g. G
8 0
3 years ago
Read 2 more answers
The overhead reach distances of adult females are normally distributed with a mean of 197.5 cm197.5 cm and a standard deviation
fiasKO [112]

Answer:

a) 5.37% probability that an individual distance is greater than 210.9 cm

b) 75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c) Because the underlying distribution is normal. We only have to verify the sample size if the underlying population is not normal.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 197.5, \sigma = 8.3

a. Find the probability that an individual distance is greater than 210.9 cm

This is 1 subtracted by the pvalue of Z when X = 210.9. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{210.9 - 197.5}{8.3}

Z = 1.61

Z = 1.61 has a pvalue of 0.9463.

1 - 0.9463 = 0.0537

5.37% probability that an individual distance is greater than 210.9 cm.

b. Find the probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

Now n = 15, s = \frac{8.3}{\sqrt{15}} = 2.14

This probability is 1 subtracted by the pvalue of Z when X = 196. Then

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{196 - 197.5}{2.14}

Z = -0.7

Z = -0.7 has a pvalue of 0.2420.

1 - 0.2420 = 0.7580

75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

The underlying distribution(overhead reach distances of adult females) is normal, which means that the sample size requirement(being at least 30) does not apply.

5 0
3 years ago
What is the volume of a small cone if:
Amiraneli [1.4K]

Answer:

Volume of smaller cone =301.44

Step-by-step explanation:

First let angle of cone be\alpha.

then sin(\alpha ) = 3/5       (For bigger triangle)

Same cone angle is for smaller one because they are similar.

cos(\alpha ) = 4/5

Now for smaller cone radius be R

3/5 =R/Slant height

Slant height =5/3R

Lateral surface area =\frac{1}{2}R^{2}\beta  [R = slant height]  

Given lateral surface area =60\pi =\frac{1}{2}(\frac{5R}{3} )^{2} \beta   ...................................1

2\pi R=\frac{5R}{3}\beta        ................................................2

\beta=\frac{6\pi }{5}

Put angle beta in equation 1 and find the value of R

R =6 cm

Height =\frac{4R}{3}

Thus volume =\frac{1}{3}\pi6^{2}*8

                     =301.44

4 0
3 years ago
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