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2 years ago

Please help! Will give points!! -Which Function is Exponential?

Mathematics

1 answer:

LiRa [457]2 years ago

4 0

Answer:

It should be C

Step-by-step explanation:

B is a quadratic function and A is a linear line.

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Janna spends 1.25 hours of her 8 hour work day answering email messages. What percentage of the work day is this time

dusya [7]

1.25 divided by 8 =0.15635×100=15.6% or round up to 16%

3 0

2 years ago

Find the value of r so the line passes through each pair of points has the give slopes

Art [367]

Answer:

$r=64$

Step-by-step explanation:

First, let's start with what we have. If we use $y=mx+b$ here's what we can put in:

$y=-4x+b$

Then we can use one of the given points to find the y-intercept. Since the only complete one is (12,10), we'll use that.

$10=-4(12)+b\\10=-48+b\\58=b$

So now we have $y=-4x+58$ .

Now we can use our other point with the missing y-value and solve for y.

$r=-4(-2)+58\\r=64$

So the missing value is 64.

Hope this helps!

7 0

2 years ago

A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar

Arisa [49]

Answer:

$\chi^2 =\frac{17-1}{12.15} 22.09 =15.87$

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates $\alpha/2 =0.05$ of the area on each tail and we got:

$\chi^2_{crit}= 7.962$

$\chi^2_{crit}=26.296$

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

$p_v =2*P(\chi^2 >15.87)=0.92$

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

$n=17$ represent the sample selected

$\alpha=0.1$ represent the significance

$s^2 =4.7^2 =22.09$ represent the sample variance

$\sigma^2_0 =3.5^2 =12.15$ represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 12.15$

Alternative hypothesis: $\sigma^2 \neq 12.15$

The statistic for this case is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

The degrees of freedom are:

$df =n-1= 17-1=16$

$\chi^2 =\frac{17-1}{12.15} 22.09 =15.87$

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates $\alpha/2 =0.05$ of the area on each tail and we got:

$\chi^2_{crit}= 7.962$

$\chi^2_{crit}=26.296$

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

$p_v =2*P(\chi^2 >15.87)=0.92$

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0

3 years ago

Easy 6th grader problem but I don't know it?<br> PLEASE HELP<br> 20 points

Alja [10]

Answer:

no it's easy u do it your self if u say it's easy

3 0

3 years ago

Help me on this it’s in the picture

yarga [219]

Answer:

x = -2

y = 3

Step-by-step explanation:

from above equation we get ,

=》y = 3x + 9

now ,

by second equation,

=》2x + 3y = 5

=》2x + 3 × ( 3x + 9 ) = 5

( since, y = 3x + 9 , by equation 1 )

=》2x + 9x + 27 = 5

=》11x = -22

=》x = -2

putting value of x in equation 1 ;

=》 y = 3x + 9

=》 y = 3 × ( -2 ) + 9

=》 y = -6 + 9

=》 y = 3

5 0

3 years ago

Read 2 more answers