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3 years ago

Help me out here pleaseeeeeeee

Mathematics

1 answer:

Eddi Din [679]3 years ago

7 0

Answer:

Answer is 0.08, I took the quiz

Step-by-step explanation:

Can I get 5 stars to brainliest

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So the answer would be16*4=64

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3 years ago

Sin(−θ)=1/5 and tanθ=√6/12 What is the value of cosθ ?

Shtirlitz [24]

$\bf sin(-\theta)\iff -sin(\theta)\qquad \qquad tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\\\\
-----------------------------\\\\
tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\implies cos(\theta)=\cfrac{sin(\theta)}{tan(\theta)}\quad 
\begin{cases}
sin(-\theta)=\cfrac{1}{5}\\\\
-sin(\theta)=\cfrac{1}{5}\\\\
sin(\theta)=-\cfrac{1}{5}\\
--------\\
tan(\theta)=\cfrac{\sqrt{6}}{12}
\end{cases}
\\\\\\
thus\qquad cos(\theta)=\cfrac{-\frac{1}{5}}{\frac{\sqrt{6}}{12}}$

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3 years ago

The velocity of an object is given by the following function defined on a specified interval. Approximate the displacement of th

harkovskaia [24]

Answer:

The displacement of the object on this intervals is 1.33 m.

Step-by-step explanation:

Given that,

The function of velocity is

$v=\dfrac{1}{2t+4}\ m/s$

For 0 ≤ t ≤8 , n = 2

We need to calculate the intervals

Using formula for intervals

For, n = 1

$\Delta x=\dfrac{t_{f}-t_{i}}{n}$

$\Delta x=\dfrac{8-0}{2}$

$\Delta x=4$

So, The intervals are (0,4), (4,8)

We need to calculate the velocity

Using given function

$v=\dfrac{1}{2t+4}$

For first interval (0,4),

Put the value into the formula

$v_{0}=\dfrac{1}{2\times0+4}$

$v_{0}=\dfrac{1}{4}$

For first interval (4,8),

Put the value into the formula

$v_{4}=\dfrac{1}{2\times4+4}$

$v_{4}=\dfrac{1}{12}$

We need to calculate the total displacement

Using formula of displacement

$D=(v_{0}+v_{4})\times(\Delta x)$

Put the value into the formula

$D=(\dfrac{1}{4}+\dfrac{1}{12})\times4$

$D=1.33\ m$

Hence, The displacement of the object on this intervals is 1.33 m.

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4 years ago

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Answer:

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3 years ago

a community program choose 16 fifth grade students every year and provide each of them with the same amount of money to attend m

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Answer: 525

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3 years ago