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snow_lady [41]
3 years ago
14

-5x -10 >30 help Hehehehehe.

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
4 0

Answer:

x<-8

Step-by-step explanation:

-5x-10>30

(add 10 to both sides)

-5x-10+10>30+10

-5x>40

\frac{-5x}{-1}<\frac{40}{-1}

(dividing through by -1 changes the sign of the inequality from "<" to ">")

5x<-40

(dividing through by 5)

\frac{5x}{5}<\frac{-40}{5\\}

x<-8

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1. -x=10y<br><br>2. y+8=-x<br><br>3. -4+7x+4=3y​
fiasKO [112]

Answer:

1 y=-1/10x

2 y=-x-8

3 y= 7/3x or 2 1/3x

Step-by-step explanation:

1 -x=10y

divide -x and 10 by 10

2 y+8=-x

subtract 8

3 -4+7x+4=3y

divide everything by 3

6 0
3 years ago
1. What are the opposite and absolute value of: a) 7.2 ____,____ b) -3.5 ____, ____ c) 5 ½ ____,____
NARA [144]

Opposite value would be either changing from a positive to a negative or from a negative to a positive.

Absolute value is always a positive value

A) 7.2, -7.2, 7.2

B) -3.5, 3.5, 3.5

C) 5 1/2, -5 1/2, 5 1/2

7 0
3 years ago
Read 2 more answers
The value of loga (30a)^3 is
postnew [5]
Part 1 of the solution.

8 0
3 years ago
Multiply. -5•-1/7•4/8. Write your answer in simplest form.
Sphinxa [80]

Answer:

5/14

Step-by-step explanation:

Multiply.

(-5 × -1 × 4) / (7 × 8)

20/56

Simplify.

5/14

7 0
3 years ago
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A lake has a large population of fish. On average, there are 2,400 fish in the lake, but this number can vary by as much as 155.
AleksAgata [21]

Answer:

Minimum population of fish in lake = 2400 - 155 = 2245

Maximum population of fish in lake = 2400 + 155 = 2555

Step-by-step explanation:

population of fish in lake = 2400

Variation of fish = 155

it means that while current population of fish is 2400, the number can increase or decrease by maximum upto 155.

For example

for increase

population of fish can 2400 + 2, 2400 + 70, 2400 + 130 etc

but it cannot be beyond 2400 + 155.

It cannot be 2400 + 156

similarly for decrease

population of fish can 2400 - 3, 2400 - 95, 2400 - 144 etc

but it cannot be less that 2400 - 155.

It cannot be 2400 - 156

Hence population can fish in lake can be between 2400 - 155 and 2400 + 155

minimum population of fish in lake = 2400 - 155 = 2245

maximum population of fish in lake = 2400 + 155 = 2555

4 0
3 years ago
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